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This is one of our many quizzes on Interpreting graphs. Click on this to access more such competitive quizzes on Graphs.

Interpreting graphs Quiz 2

mathematics

 Below is the graph showing the average highest temperature of Bangalore over $11$ years find the percentage change in the average temperature from the year $2002$ to the last year. <img  src="https://cmds-vedantu.s3.ap-southeast-1.amazonaws.com/prod/question-sets/c69f2628-731b-4ab4-b9e6-88a27ad2484a1826930838766986998.png"/>

 First find average highest temperatures of the respective years from the graph and then find the percentage difference using this formula $\dfrac{{a - b}}{a} \times 100,\;{\text{where}}\;a\;{\text{and}}\;b$ are the initial value and the final value respectively.

Average highest temperature in the year $2002 = {45^0}C$  $ \\ $ Average highest temperature in the last year, i.e. $2010 = {15^0}C$  $ \\ $ So percentage change, $ \\  = \dfrac{{45 - 15}}{{45}} \times 100 \\   = \dfrac{{30}}{{45}} \times 100 = 66.7\%  \\  $ 

 Observe the graph and calculate the distance travelled in last two hours <img  src="https://cmds-vedantu.s3.ap-southeast-1.amazonaws.com/prod/question-sets/b6b8cb78-8695-4e38-941a-09936478ea0e1152384158853303163.png"/>

 Find the last two hours and the position on those timings and then subtract them to get the distance

The last two hour goes from $8{\text{PM}}\;{\text{to}}\;{\text{10PM}}$ and to calculate the distance travelled during this interval, $D = 8 - 0 = 8km$ 

 Study the below graph showing the production of two companies A and B over years and find out in $1995$ the production of company A, approximately what percent of that in $2001$<img  src="https://cmds-vedantu.s3.ap-southeast-1.amazonaws.com/prod/question-sets/8ed41615-d338-4ec0-baae-24b3a0d8d91d7293057725074744059.png"/>

 Find data from the graph and then the percentage. If we have to calculate $a$ in comparison to percent of $b$ then it is given as $\dfrac{a}{b} \times 100$   

Production of company A on $1995 = 3 \times {10^5}$  $ \\ $ Production of company A on $2001 = 12 \times {10^5}$ $ \\ $ Required percentage $ = \dfrac{3}{{12}} \times 100 = 25\% $ 

 In the below bar graph, marks are given to a student in respective subjects. The passing percentage is $40\% $, find out if the student is passed or not? <img  src="https://cmds-vedantu.s3.ap-southeast-1.amazonaws.com/prod/question-sets/47436e3f-3230-421d-b0f9-e0c7ef7274a51774339959495050892.png"/>

 Find out the marks of the student in each subject from the graph and then calculate the percentage respectively.

Marks in English, $m_1 = 55$ $ \\ $ Marks in Mathematics, $m_2 = 90$ $ \\ $ Marks in Hindi, $m_3 = 40$ $ \\ $ Marks in Science, $m_4 = 80$ $ \\ $ Marks in S-St, $m_5 = 20$ $ \\ $ Therefore percentage $ \\  p = \dfrac{{m_1 + m_2 + m_3 + m_4 + m_5}}{{{\text{Total}}\;{\text{marks}}}} \times 100\%  \\    = \dfrac{{55 + 90 + 40 + 80 + 20}}{{500}} \times 100\%  \\    = \dfrac{{285}}{{500}} \times 100\%  = 57\%  \\  $ So the student is passed with $57\%$

 Expenditure of company B in the year 1998 was $4$ million rupees, its income on that year will be given as $ \\ $ <img  src="https://cmds-vedantu.s3.ap-southeast-1.amazonaws.com/prod/question-sets/079c7b92-1b0e-4b22-8723-23735970bd813777357800631445014.png"/>

 First find the profit by use of following formula $P = p \times E,\;{\text{where}}\;P,p\;{\text{and}}\;E$ are profit, profit percentage and expenditure respectively. And after this, calculate the income which can be calculated as the sum of profit and expenditure.

Profit earned by the company B in year 1998 will be given as $ \\  P = \dfrac{{50}}{{100}} \times 4,000,000 \\    = 2,000,000{\text{rupees}} \\  $  Now, Income $ = $ Expenditure $ + $ Profit $ \\ $ Income $ = 4,000,000 + 2,000,000 = Rs.6,000,000$  $ \\ $ Therefore income $ = 6$ million rupees