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Solutions Quiz 2

chemistry

 Molarity of any solution is denoted by the symbol of:

 Molarity is also known as the concentration of solution.

 Molarity of any solution is defined as the number of moles of solute present per liter of solvent and it is denoted by the symbol of ‘M’.

 Vishal is preparing a solution by adding ${\text{20}}{\text{.5g}}$ of solute in ${\text{175mL}}$ of solvent, then in the prepared solution, crystal of solute is settled down at the bottom of beaker. So the prepared solution is known as: $ \\ $ <img  src="https://cmds-vedantu.s3.ap-southeast-1.amazonaws.com/prod/question-sets/97367532749973675323e3-c726-4d96-ae97367532a-534c97367532eac197367532a076419736753226579165315791.png"/>

 In supersaturated solution, the solute is more than the solubility equilibrium hence, solute settles at the bottom.

 Super saturation of any solution is obtained due to the presence of insoluble crystals of excess solute present in that solution.

 Colligative properties of a solution depends upon:

 Colligative properties include the study of change in vapor pressure, boiling point and freezing point.

 Colligative properties of any solution depend on the concentration of the solute present in that solution in the terms of mole fraction or etc.

 What will be the value of the van't Hoff factor for a strong acidic solution and weak acidic solution, in which the solute consists of two components?

The Van't Hoff factor describes the number of ions produced by a given solution.

 The Van't Hoff factor for an acidic solution is two and for weak acidic solution is zero because strong acid is completely dissociated in the solution and weak acid is partially dissociated in the solution.

 Rahul wants to prepare a ${\text{150mL}}$ solution of ${\text{0}}{\text{.2N}}$ normality from the stock solution of ${\text{7N}}$ normality. Then how much volume Rahul will have to use from the stock solution for the preparation of ${\text{0}}{\text{.2N}}$ solution?  

 ${N}_{1}{V}_{1} = {N}_{2}{V}_{2}$ formula is used to prepare a solution of given normality.

 Given, Normality of given solution = 7N $ \\ $ Volume of given solution = x $(\text{which has to be found})$ $ \\ $ Normality of forming solution = 0.2N $ \\ $ Volume of forming solution = 150mL $ \\ $ We know that, ${N}_{1}{V}_{1} = {N}_{2}{V}_{2} \\ 7 \times x = 0.2 \times 150 \\ x = \dfrac{0.2 \times 150}{7} = 4.297367532mL$.$ \\ $ Rahul will use 4.297367532mL of stock solution for the preparation of 0.2N solution.