Free Study Material

NCERT Solutions

NCERT Books

Revision Notes

Practice Problems

This is one of our many quizzes on Solubility. Click on this to access more such competitive quizzes on Mixtures.

Solubility Quiz 2

chemistry

 Observe the following chemical reaction and answer the given question.<br>$2{{H}_{2}}+{{O}_{2}}\rightleftharpoons 2{{H}_{2}}O$<br>&nbsp;Under what condition the forward reaction is favored?

 Le chatlier’s principle also known by the name equilibrium law which is used to predict the effect of different changes on a system in chemical equilibrium. 

Le chatlier’s principle states that increasing the concentration of reactants results in shifting the equilibrium in favor of products i.e. favors the forward reaction so in the gives reaction also if we increase the concentration of reactant then forward reaction is favored.

 Write solubility product equation for magnesium chloride $MgC{{l}_{2}}$.

 Solubility products generally depend on the temperature or we can say that it is directly proportional to the temperature i.e. it increases with increase in temperature and decreases with decrease in temperature.

${{K}_{sp}}$ is a solubility product which can be defined as the equilibrium constant of any solution whose value is dependent on temperature; basically it is directly proportional to temperature. The basic equation for ${{K}_{sp}}$ can be written as ${{K}_{sp}}={{[{{A}^{+}}]}^{a}}{{[{{B}^{-}}]}^{b}}$, where ${{A}^{+}}$ cation in aqueous solution, ${{B}^{-}}$anion in an aqueous solution and a,b relative concentrations of a and b.

 If the solubility is in the range of 0.01M-0.1M then solution is said to be

 Solubility can be defined as the tendency of solute to get dissolved in a solvent where solute is the substance present in lower amounts and solvent in which it gets dissolved is present in a higher amount. 

 Solubility is the property of solid, liquid or gaseous chemical substances known by the name solute dissolve in solid, liquid or gaseous solvent. If the solubility is greater than 1 M then it is highly soluble in nature after that solubility goes on decreasing. The solubility is in the range of 0.01M-0.1M then the solution is said to be a slightly soluble solution.

 Calculate the solubility product of sodium chloride if it contains $2.0\times {{10}^{-4}}$mol of $N{{a}^{+}}/L$ and $1.9\times {{10}^{-6}}C{{l}^{-}}/L$

 ${{K}_{sp}}$ is a solubility product which can be defined as the equilibrium constant of any solution whose value is dependent on temperature; basically it is directly proportional to temperature. The equation of sodium chloride can be shown as:<br>$NaCl\to N{{a}^{+}}+C{{l}^{-}}$; ${{K}_{sp}}={{[Na]}^{+}}{{[Cl]}^{-}}$; ${{K}_{sp}}=[2\times {{10}^{-4}}][1.9\times {{10}^{-6}}]=3.8\times {{10}^{-10}}$

 Observe the graph and answer the given question. <img  src="https://cmds-vedantu.s3.ap-southeast-1.amazonaws.com/prod/question-sets/126d0d86-0b67-40f7-8834-b93e5d6906a47567228680972246710.png"/><br>What is the effect of temperature on the solubility of the solute?

  Solubility can be defined as the tendency of solute to get dissolved in a solvent where solute is the substance present in lower amounts and solvent in which it gets dissolved is present in a higher amount.

 Solubility curve gives us the graphical representation between the solubility and temperature. This curve plots the changes of the solubility of a solid at different temperatures in a solvent. In graph variation in temperature plotted on x-axis and solubility is plotted on y-axis.  