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This is the second of our many quizzes on Precipitates. Click on this to access more such competitive quizzes on General Chemistry.

Precipitates Quiz 2

chemistry

  Observe the following chemical reaction and find the chemical which Chemical Reactions?<br>$BaN{{O}_{3}}(aq)+CaC{{l}_{2}}(aq)\to BaC{{l}_{2}}+CaN{{O}_{3}}$

 Sparingly soluble compounds are going to form a precipitate at the bottom of the vessel.  

  The given chemical reaction is as follows. $ \\ BaN{{O}_{3}}(aq)+CaC{{l}_{2}}(aq)\to BaC{{l}_{2}}+CaN{{O}_{3}}\\ $ In the above chemical reaction barium nitrate is going to react with calcium chloride and forms barium chloride and calcium nitrate as the products. The products barium chloride and calcium nitrate are soluble in water. So there is no precipitate that is going to form in the given chemical reaction.

 In the blow image there are three test tubes contains three types of solutions $ \\ $<img  src="https://cmds-vedantu.s3.ap-southeast-1.amazonaws.com/prod/question-sets/068defe5-3cd7-45be-bd78-eef3f13e2c291887730742832500185.png"/> $ \\ $ Identify which of the test tubes contains precipitate and which test tube contains a homogenous solution.  

 If there is any insoluble chemical present in the test tube it is called precipitate and if the solution is transparent in nature then it is called a clear solution.

  In the test tube A we can see that it is transparent and does not contain any precipitate at the bottom. So test tube A is clear. Coming to test tube C, we can clearly see a chemical which is present at the bottom of the test tube means test tube C contains precipitate.

 Copper chloride reacts with sodium hydroxide and forms the product as per below chemical reaction. $CuC{{l}_{2}}+NaOH\to Cu{{(OH)}_{2}}+NaCl$ .In the above chemical reaction which chemical is going to get precipitated?

 Sparingly soluble compounds are going to form a precipitate at the bottom of the vessel. 

 &nbsp;In the given chemical reaction cupric chloride reacts with sodium hydroxide and forms cupric hydroxide and sodium chloride. The chemical cupric hydroxide is not soluble in the water. So, cupric hydroxide is the precipitate going to form in the given chemical reaction.

 During a chemical reaction between two different chemicals why there is a formation of precipitate during or after the completion of the chemical reaction. 

 Sparingly soluble compounds are going to form a precipitate at the bottom of the vessel.

 &nbsp;The reason behind the formation of the precipitate after the chemical reaction is that the products formed during the chemical reaction or after the completion of the chemical reaction are less soluble in the respective solvent. Due to this reason the insoluble products are going to form a precipitate at the bottom of the vessel.

  There are THREE incomplete chemical reactions below. $AgN{{O}_{3}}(aq)+2KBr(aq)\to ? \\ Ca{{(N{{O}_{3}})}_{2}}+{{K}_{2}}C{{O}_{3}}(aq)\to ? \\ LiN{{O}_{3}}(aq)+Na{{C}_{2}}{{H}_{3}}{{O}_{2}}\to ?$ Observe the above chemical reactions and find the products which are going to form in the form of a precipitate after the chemical reaction.

 The compounds or products which are less soluble in water or in the respective solvent are going to form in the form of a precipitate.

The Products formed in the given chemical reaction are as follows. $ \\ AgN{{O}_{3}}(aq)+2KBr(aq)\to AgBr\text{ +KN}{{\text{O}}_{\text{3}}} \\ Ca{{(N{{O}_{3}})}_{2}}+{{K}_{2}}C{{O}_{3}}(aq)\to CaC{{O}_{3}}+{{K}_{2}}N{{O}_{3}} \\ LiN{{O}_{3}}(aq)+Na{{C}_{2}}{{H}_{3}}{{O}_{2}}\to Li{{C}_{2}}{{H}_{3}}{{O}_{2}}+NaN{{O}_{3}} \\ $ The products formed in the first two Precipitates are insoluble and form a precipitate at the bottom of the vessel. $ \\  \text{(a) AgBr and} KN{{O}_{3} (b)} CaC{{O}_{3}} \text{ and } {{K}_{2}}N{{O}_{3}}$