Write three consecutive whole numbers occurring just before 567890?

Hint: Here we need to find the three consecutive occurring numbers before the given number in the question, here the condition is to write the whole numbers, which means the numbers should not contain any decimal form and only integer value should be present.

Complete answer:
In order to solve the given question here we need to understand that whole numbers are the numbers which are not in decimal form and only integer value is present, and here we need to write three consecutive whole number before the given number and should be occurring, which means the numbers should be preceding by one to the next number, on solving we get:
\[
   \Rightarrow 567890 - 1 = 567889 \\
   \Rightarrow 567889 - 1 = 567888 \\
   \therefore 567888 - 1 = 567887 \\
 \]
Hence, we get the correct answer for the above question.

Note:
Consecutive whole numbers can simply find out just by adding one to the number whose next consecutive number has to be calculated. The numbers that follow each other continuously are the consecutive numbers, without gaps.