Write the quotient when the difference of a two-digit number 73 and number obtained by reversing the digits is divided by
(i) 9
(ii) the difference of digits.

Hint: Here, we can see that we are given a two-digit number 73. We know that the digit 3 is in one place, and the digit 7 is in the tens place.
We can clearly say that, in the number obtained on reversing the digits, the digit at one's place will be 7 and the digit at tens place will be 3. Thus, the reversed number is 37.

Complete step by step answer:
According to the question, we now need to find the difference between our original number and the reversed number.
We can see that
73 – 37 = 36.
(i) In this part, the difference needs to be divided by 9. Thus, we need to divide 36 by 9.
We know that $\dfrac{36}{9}=4$.
Hence, 4 is the quotient when the difference of a two-digit number 73 and number obtained by reversing the digits is divided by 9.
(ii) In this part, the difference needs to be divided by the difference of digits.
We know that the difference of digits, 7 – 3 = 4.
Thus, we need to divide 36 by 4.
We know that $\dfrac{36}{4}=9$.
Hence, 9 is the quotient when the difference of a two-digit number 73 and number obtained by reversing the digits is divided by the difference of digits.

Note: Here, in the (ii) part of this question, it is really important to understand that the phrase ‘difference of digits’ means the difference between the digits of our original number, that is, difference between the digits 7 and 3, which is equal to 4.