How do you write the balanced chemical, complete ionic and net ionic equation for the reaction between aqueous solutions of sodium carbonate and calcium chloride?

Hint Balancing of a chemical equation means that the number of atoms present on the reactant side should be equal to that in the product side. The given reaction is a double displacement reaction and writes the equation in the ionic form to reach the required answer.

Complete step – by – step answer:
In the previous classes of chemistry, we have studied in detail about how to write the reactions with the given data and also about balancing the given chemical equation.
We shall now see how to write the above given data in the form of an ionic chemical equation and balancing it.
- The reaction between sodium carbonate and calcium chloride is the double displacement reaction where two soluble ionic compounds react in aqueous media to form an insoluble solid.
- The reactions in the form of the net ionic equation can be written as shown below in detail.
- These compounds given are the ionic compounds and in the aqueous solution they dissociate.
Dissociation of sodium carbonate is as shown below,
\[N{{a}_{2}}C{{O}_{3}}(aq)\to 2N{{a}^{+}}(aq)+CO_{3}^{2-}(aq)\]
Similarly, the dissociation of calcium chloride will be,
\[CaC{{l}_{2}}(aq)\to C{{a}^{2+}}(aq)+2C{{l}^{-}}(aq)\]
When we mix these two solutions calcium ion pair with the carbonate ion and forms insoluble calcium carbonate and this can be written in ionic equation as,
\[2N{{a}^{+}}(aq)+CO_{3}^{2-}(aq)+C{{a}^{2+}}(aq)+2C{{l}^{-}}(aq)\to CaC{{O}_{3}}(s)\downarrow +2N{{a}^{+}}(aq)+2C{{l}^{-}}(aq)\]
 When the spectator ions are cancelled out in the above equation, we get the final form of net equation as,
\[CO_{3}^{2-}(aq)+C{{a}^{2+}}(aq)\to CaC{{O}_{3}}(s)\downarrow \]
 Here, the sodium and chloride ions are form in two moles that is the actual overall equation will be,
\[N{{a}_{2}}C{{O}_{3}}(aq)+CaC{{l}_{2}}(aq)\to CaC{{O}_{3}}(s)\downarrow +2NaCl(aq)\]

Note: Note that the spectator ligands are those ions or the compound which exists at both the sides of the equation in common so that they are cancelled easily and the remaining compounds make the equation.