How to write an equation for a rational function with : Horizontal asymptote at \[y = 5\]
Answer
591.3k+ views
Hint: In order to determine the equation for rational function with horizontal asymptote \[y = 5\].Assume the rations equation as\[y = \dfrac{{p\left( x \right)}}{{q\left( x \right)}}\]. Determine the $ q\left( x \right) $ such that it should not have any solution as there is no vertical asymptote. For the horizontal asymptote. Determine the $ p\left( x \right) $ such that the ratio of highest degrees of both \[p\left( x \right)\]and \[q\left( x \right)\]is equal to $ 5 $ .
Complete step-by-step answer:
We are given horizontal asymptote for some rational function as \[y = 5\].
Let’s assume a rational function \[y = \dfrac{{p\left( x \right)}}{{q\left( x \right)}}\]where x is the variable.
Since according to the question, the rational function has no vertical asymptote. So for no vertical asymptote the denominator should not have any solution.
Thus, $ q\left( x \right) $ is a function which has no solution or is in the form of sum of squares.
Let $ q\left( x \right) = {x^2} + 4 $
Now to have horizontal asymptote \[y = 5\], we should have $ p\left( x \right) $ such that the ratio between the highest degree of $ p\left( x \right) $ and $ q\left( x \right) $ equal to $ 5 $ .
For example let $ p\left( x \right) = 5{x^2} $
Hence, we have the rational function as $ y = \dfrac{{5{x^2}}}{{{x^2} + 4}} $ with horizontal asymptote as $ y = 5 $
Therefore, an equation of rational function with horizontal asymptote is $ y = \dfrac{{5{x^2}}}{{{x^2} + 4}} $ .
So, the correct answer is “ $ y = \dfrac{{5{x^2}}}{{{x^2} + 4}} $ .”.
Note: Remember that for the rational equation with horizontal asymptote $ y = 5 $ , you can have many rational equations. In the solution we have considered just an example. Students can also form different equations satisfying the conditions and requirements for the equation mentioned in the solution.
Vertical asymptotes for rational functions are found by setting the denominator equivalent to 0. This additionally assists with finding the domain. The domain can NOT contain that number
Complete step-by-step answer:
We are given horizontal asymptote for some rational function as \[y = 5\].
Let’s assume a rational function \[y = \dfrac{{p\left( x \right)}}{{q\left( x \right)}}\]where x is the variable.
Since according to the question, the rational function has no vertical asymptote. So for no vertical asymptote the denominator should not have any solution.
Thus, $ q\left( x \right) $ is a function which has no solution or is in the form of sum of squares.
Let $ q\left( x \right) = {x^2} + 4 $
Now to have horizontal asymptote \[y = 5\], we should have $ p\left( x \right) $ such that the ratio between the highest degree of $ p\left( x \right) $ and $ q\left( x \right) $ equal to $ 5 $ .
For example let $ p\left( x \right) = 5{x^2} $
Hence, we have the rational function as $ y = \dfrac{{5{x^2}}}{{{x^2} + 4}} $ with horizontal asymptote as $ y = 5 $
Therefore, an equation of rational function with horizontal asymptote is $ y = \dfrac{{5{x^2}}}{{{x^2} + 4}} $ .
So, the correct answer is “ $ y = \dfrac{{5{x^2}}}{{{x^2} + 4}} $ .”.
Note: Remember that for the rational equation with horizontal asymptote $ y = 5 $ , you can have many rational equations. In the solution we have considered just an example. Students can also form different equations satisfying the conditions and requirements for the equation mentioned in the solution.
Vertical asymptotes for rational functions are found by setting the denominator equivalent to 0. This additionally assists with finding the domain. The domain can NOT contain that number
Recently Updated Pages
If x a + bt + ct2 where x is in meters and t is in class 11 physics CBSE

A car covers the first half distance between two places class 11 physics CBSE

The resultant of two vectors overrightarrow P and overrightarrow class 11 physics CBSE

Find the value of cos 135 class 11 maths CBSE

A mass M is held in place by an applied force F and class 11 physics CBSE

A solution of glucose in water is labelled as 10 dfracwv class 11 chemistry CBSE

Trending doubts
Find the value of the expression given below sin 30circ class 11 maths CBSE

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Draw a diagram of nephron and explain its structur class 11 biology CBSE

10 examples of friction in our daily life

Proton was discovered by A Thomson B Rutherford C Chadwick class 11 chemistry CBSE

Bond order ofO2 O2+ O2 and O22 is in order A O2 langle class 11 chemistry CBSE

