How do you write an equation (a) in slope-intercept form and (b) in standard form for the line passing through \[\left( 1,7 \right)\] and perpendicular to \[3x+7y=1\]?
Answer
602.4k+ views
Hint: The slope intercept form of a line is \[y=mx+b\], here m is the slope of the line and b is the Y-intercept of the line. We also have the standard form of the equation which is expressed as \[ax+by+c=0\]. To express an equation in this form, we have to take all terms to one side of the equation leaving zero to the other side. We should also know that the slope of a line perpendicular to a line with slope m equals \[\dfrac{-1}{m}\].
Complete step by step solution:
We are asked to find the equation of the straight and which is perpendicular to the line \[3x+7y=1\] and passes through \[\left( 1,7 \right)\]. We can easily find the slope of this given line as \[\dfrac{-3}{7}\]. The line we want to find is perpendicular to the given line, hence its slope value equals \[\dfrac{-1}{\dfrac{-3}{7}}=\dfrac{7}{3}\].
We will use the slope intercept form of the equation of a straight line for which the value of m is \[\dfrac{7}{3}\]. The slope intercept form of the equation is \[y=mx+b\] here m is the slope of the line and b is the Y-intercept of the line.
Substituting the values of the variable m in the slope intercept form of the equation, we get
\[\Rightarrow y=\dfrac{7}{3}x+b\]
This equation has still an unknown constant. To find the value of this constant, we will use the other information about the line. As the line passes through the point \[\left( 1,7 \right)\], this point must satisfy the equation of the line. Substituting the point in the equation, we get
\[\Rightarrow 7=\dfrac{7}{3}(1)+b\]
Solving the above equation, we get
\[\Rightarrow b=\dfrac{14}{3}\]
(a) Now we have values of both m and b, hence, the slope intercept form of the equation is\[y=\dfrac{7}{3}x+\dfrac{14}{3}\].
(b) To express this in standard form, we need to take all terms to one side and get rid of the fractions. The standard form of the equation is \[7x-3y+14=0\] or \[7x-3y=-14\].
We can also graph the equation as follows:
Note: To solve these types of questions, we should know the properties of straight lines and its different forms of equation. The property of slopes should also be known, here we used the property of slopes of perpendicular lines which states that the slope of a line perpendicular to line with slope m equals \[\dfrac{-1}{m}\].
Complete step by step solution:
We are asked to find the equation of the straight and which is perpendicular to the line \[3x+7y=1\] and passes through \[\left( 1,7 \right)\]. We can easily find the slope of this given line as \[\dfrac{-3}{7}\]. The line we want to find is perpendicular to the given line, hence its slope value equals \[\dfrac{-1}{\dfrac{-3}{7}}=\dfrac{7}{3}\].
We will use the slope intercept form of the equation of a straight line for which the value of m is \[\dfrac{7}{3}\]. The slope intercept form of the equation is \[y=mx+b\] here m is the slope of the line and b is the Y-intercept of the line.
Substituting the values of the variable m in the slope intercept form of the equation, we get
\[\Rightarrow y=\dfrac{7}{3}x+b\]
This equation has still an unknown constant. To find the value of this constant, we will use the other information about the line. As the line passes through the point \[\left( 1,7 \right)\], this point must satisfy the equation of the line. Substituting the point in the equation, we get
\[\Rightarrow 7=\dfrac{7}{3}(1)+b\]
Solving the above equation, we get
\[\Rightarrow b=\dfrac{14}{3}\]
(a) Now we have values of both m and b, hence, the slope intercept form of the equation is\[y=\dfrac{7}{3}x+\dfrac{14}{3}\].
(b) To express this in standard form, we need to take all terms to one side and get rid of the fractions. The standard form of the equation is \[7x-3y+14=0\] or \[7x-3y=-14\].
We can also graph the equation as follows:
Note: To solve these types of questions, we should know the properties of straight lines and its different forms of equation. The property of slopes should also be known, here we used the property of slopes of perpendicular lines which states that the slope of a line perpendicular to line with slope m equals \[\dfrac{-1}{m}\].
Recently Updated Pages
Write structures of the following compounds i 2 Chloro3methylpentane class 11 chemistry CBSE

What is BLO What is the full form of BLO class 8 social science CBSE

Explain the Treaty of Vienna of 1815 class 10 social science CBSE

A Paragraph on Pollution in about 100-150 Words

XIX+XXX A 49 B 51 C 55 D 44 class 5 maths CBSE

If x a + bt + ct2 where x is in meters and t is in class 11 physics CBSE

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Find the value of the expression given below sin 30circ class 11 maths CBSE

What do you mean by retardation What is its SI uni class 11 physics CBSE

Draw a diagram of nephron and explain its structur class 11 biology CBSE

10 examples of friction in our daily life

Difference between physical and chemical change class 11 chemistry CBSE

