What is the width of a rectangle whose area is 60 square inches and whose length is 5 inches?

Hint: Assume the width (breadth) of the rectangle as b and its length as l. Now, apply the formula for the area of a rectangle given as $A=b\times l$ where A is the area. Substitute the given values of A = 60 square inches and l = 5 inches and calculate the value of b to get the answer.

Complete step by step solution:
Here we have been provided with the area of a rectangle as 60 square inches with its length as 5 inches. We are asked to find the width or breadth of this rectangle.

Now, in the above figure we have drawn a rectangle ABCD with its breadth as b and length as l. We know that the area of a rectangle is the product of its length and breadth, so mathematically we have $A=b\times l$, where A denotes the area.
Substituting the given values of A = 60 square inches and l = 5 inches we get,
$\begin{align}
  & \Rightarrow 60=b\times 5 \\
 & \Rightarrow b=12 \\
\end{align}$
Hence, the width of the rectangle is 12 inches.

Note: You must remember the formula of the area of all the special quadrilaterals like square, rectangle, rhombus, trapezium, parallelogram etc. Note that the unit of width will be inches because area is in square inch and height is also in inch. Do not try to convert them into other units of measurement of distance unless told to do so.