While mentioning acceleration the time is mentioned two times. Why?
Answer
546.9k+ views
Hint: Before we get to the question, let's talk about the acceleration. In mechanics, acceleration is the rate at which an object's velocity changes with respect to time. The term "acceleration" refers to a quantity that is measured in vectors (in that they have magnitude and direction). The SI unit for acceleration is the metre per second squared $\left( {m \cdot {s^{ - 2}}} \right)$.
Complete step by step answer:
The rate of change of velocity with time is called acceleration, while the rate of change of displacement with time is called velocity. Because both words are time dependent, time is mentioned twice in the case of acceleration.
Explanation: The rate of change of velocity is referred to as acceleration.
$a = \dfrac{v}{t}$
The rate of change of displacement is called velocity.
$v = \dfrac{s}{t}$
As a result, acceleration can be expressed as,
$a = \dfrac{v}{t} \\
\Rightarrow a= \dfrac{{\dfrac{s}{t}}}{t} \\
\therefore a= \dfrac{s}{{{t^2}}}$
As a result, the unit of acceleration is \[m \cdot {s^2}\].
As a result, while describing acceleration, time is taken into account twice.
Note: It should be emphasised that it is impossible to tell whether an observable force is due to gravity or acceleration unless the object's state of motion is known; gravity and inertial acceleration have identical effects. The equivalence principle, coined by Albert Einstein, states that only observers who feel no force at all, including gravity, are justified in judging that they are not accelerating.
Complete step by step answer:
The rate of change of velocity with time is called acceleration, while the rate of change of displacement with time is called velocity. Because both words are time dependent, time is mentioned twice in the case of acceleration.
Explanation: The rate of change of velocity is referred to as acceleration.
$a = \dfrac{v}{t}$
The rate of change of displacement is called velocity.
$v = \dfrac{s}{t}$
As a result, acceleration can be expressed as,
$a = \dfrac{v}{t} \\
\Rightarrow a= \dfrac{{\dfrac{s}{t}}}{t} \\
\therefore a= \dfrac{s}{{{t^2}}}$
As a result, the unit of acceleration is \[m \cdot {s^2}\].
As a result, while describing acceleration, time is taken into account twice.
Note: It should be emphasised that it is impossible to tell whether an observable force is due to gravity or acceleration unless the object's state of motion is known; gravity and inertial acceleration have identical effects. The equivalence principle, coined by Albert Einstein, states that only observers who feel no force at all, including gravity, are justified in judging that they are not accelerating.
Recently Updated Pages
If x a + bt + ct2 where x is in meters and t is in class 11 physics CBSE

A car covers the first half distance between two places class 11 physics CBSE

The resultant of two vectors overrightarrow P and overrightarrow class 11 physics CBSE

Find the value of cos 135 class 11 maths CBSE

A mass M is held in place by an applied force F and class 11 physics CBSE

A solution of glucose in water is labelled as 10 dfracwv class 11 chemistry CBSE

Trending doubts
Find the value of the expression given below sin 30circ class 11 maths CBSE

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Draw a diagram of nephron and explain its structur class 11 biology CBSE

10 examples of friction in our daily life

Proton was discovered by A Thomson B Rutherford C Chadwick class 11 chemistry CBSE

Bond order ofO2 O2+ O2 and O22 is in order A O2 langle class 11 chemistry CBSE

