Volume-Temperature graph at atmospheric pressure for a monoatomic gas ( V in m$^3$, T in $^\circ$C) is_______
(A).
(B).
(C).
(D).
Answer
653.1k+ views
Hint: We all know that a gas follows the ideal gas equation at low pressure and high temperature. One of the parameters can be varied concerning the other parameters by keeping all extra parameters as constant. We can then analyze the variation of pressure, temperature, and volume to each other.
Complete step by step solution:
We know about the ideal gas equation that,
$PV = nRT$
Here, P is the absolute pressure of the gas, V is the volume occupied by the gas, R is the universal gas constant, and T is the absolute temperature, n is the number of moles of a gas.
For deriving this equation, the gas is assumed to be at low pressure and high temperature. Suppose if the pressure of the gas is held constant, then the relationship becomes linear between volume and temperature as R and n along with P is steady now. We get the relation as,
$V = \dfrac{{nR}}{P}T$
Since $\dfrac{{nR}}{P} = C$ it is constant, so the above relation becomes,
$V = CT$
Here we can express the relation as,
$V \propto T$
Here, V is having a linear relation with T. So, there is a straight-line relation between V and T.
Therefore, there must be a straight-line relation between V and T, and the correct option is (D).
Note: Also, we can analyze that when the volume is held constant, the pressure can be varied to temperature and follows a linear relation with temperature. Here the pressure that we are using is absolute and not gauge pressure.
Complete step by step solution:
We know about the ideal gas equation that,
$PV = nRT$
Here, P is the absolute pressure of the gas, V is the volume occupied by the gas, R is the universal gas constant, and T is the absolute temperature, n is the number of moles of a gas.
For deriving this equation, the gas is assumed to be at low pressure and high temperature. Suppose if the pressure of the gas is held constant, then the relationship becomes linear between volume and temperature as R and n along with P is steady now. We get the relation as,
$V = \dfrac{{nR}}{P}T$
Since $\dfrac{{nR}}{P} = C$ it is constant, so the above relation becomes,
$V = CT$
Here we can express the relation as,
$V \propto T$
Here, V is having a linear relation with T. So, there is a straight-line relation between V and T.
Therefore, there must be a straight-line relation between V and T, and the correct option is (D).
Note: Also, we can analyze that when the volume is held constant, the pressure can be varied to temperature and follows a linear relation with temperature. Here the pressure that we are using is absolute and not gauge pressure.
Recently Updated Pages
If x a + bt + ct2 where x is in meters and t is in class 11 physics CBSE

A car covers the first half distance between two places class 11 physics CBSE

The resultant of two vectors overrightarrow P and overrightarrow class 11 physics CBSE

Find the value of cos 135 class 11 maths CBSE

A mass M is held in place by an applied force F and class 11 physics CBSE

A solution of glucose in water is labelled as 10 dfracwv class 11 chemistry CBSE

Trending doubts
Find the value of the expression given below sin 30circ class 11 maths CBSE

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Draw a diagram of nephron and explain its structur class 11 biology CBSE

10 examples of friction in our daily life

Proton was discovered by A Thomson B Rutherford C Chadwick class 11 chemistry CBSE

Bond order ofO2 O2+ O2 and O22 is in order A O2 langle class 11 chemistry CBSE

