How do you use the properties of summation to evaluate the sum of \[\sum {i({i^2} + 1)} \]from i =1 to 10?
Answer
621.9k+ views
Hint: Here in this question, we have to find the summation of the given term. The summation is nothing but adding the terms of the sequence or the function. As in the question it is mentioned that the value of i ranges from 1 to 10. By substituting the value of i we determine the solution for the given question.
Complete step-by-step solution:
The summation is another name for addition. The numbers in a sequence should be added.
Now consider \[\sum {i({i^2} + 1)} \], here the value of i ranges from 1 to 10.
Therefore we have
\[ \Rightarrow \sum\limits_{i = 1}^{10} {i({i^2} + 1)} \]
Substituting the value of i from 1 to 10. While substituting the values for i the summation symbol will not be considered and written. So applying the summation we have
\[
\Rightarrow 1({1^2} + 1) + 2({2^2} + 1) + 3({3^2} + 1) + 4({4^2} + 1) + 5({5^2} + 1) + 6({6^2} + 1) + 7({7^2} + 1) + \\
8({8^2} + 1) + 9({9^2} + 1) + 10({10^2} + 1) \\
\]
Squaring the terms which involves the term power 2.
\[
\Rightarrow 1(1 + 1) + 2(4 + 1) + 3(9 + 1) + 4(16 + 1) + 5(25 + 1) + 6(36 + 1) + 7(49 + 1) + \\
8(64 + 1) + 9(81 + 1) + 10(100 + 1) \\
\]
Add the terms or the constants which are present in the braces. On adding the terms we have
\[ \Rightarrow 1(2) + 2(5) + 3(10) + 4(15) + 5(26) + 6(37) + 7(50) + 8(65) + 9(82) + 10(101)\]
If the term is in the braces and there is no arithmetic operation then we apply the multiplication arithmetic operation to the terms.
So on multiplying we get
\[ \Rightarrow 2 + 10 + 30 + 60 + 130 + 222 + 350 + 520 + 738 + 1010\]
Between the two terms there is a + symbol. This implies that there we use additional arithmetic operations. Therefore on adding we get
\[ \Rightarrow 3072\]
Hence by the properties of summation we have evaluated the summation.
Therefore \[ \Rightarrow \sum\limits_{i = 1}^{10} {i({i^2} + 1)} = 3072\]
Note: The summation symbol is usually represented by \[\sum\limits_{}^{} {} \]. The summation is as defined as \[\sum\limits_{k = 1}^n {{a_k}} = {a_1} + {a_2} + {a_3} + ... + {a_n}\], this the main property of summation. We obtain the sequence and then by adding the sequence we obtain the value. The sequence is written on some rule.
Complete step-by-step solution:
The summation is another name for addition. The numbers in a sequence should be added.
Now consider \[\sum {i({i^2} + 1)} \], here the value of i ranges from 1 to 10.
Therefore we have
\[ \Rightarrow \sum\limits_{i = 1}^{10} {i({i^2} + 1)} \]
Substituting the value of i from 1 to 10. While substituting the values for i the summation symbol will not be considered and written. So applying the summation we have
\[
\Rightarrow 1({1^2} + 1) + 2({2^2} + 1) + 3({3^2} + 1) + 4({4^2} + 1) + 5({5^2} + 1) + 6({6^2} + 1) + 7({7^2} + 1) + \\
8({8^2} + 1) + 9({9^2} + 1) + 10({10^2} + 1) \\
\]
Squaring the terms which involves the term power 2.
\[
\Rightarrow 1(1 + 1) + 2(4 + 1) + 3(9 + 1) + 4(16 + 1) + 5(25 + 1) + 6(36 + 1) + 7(49 + 1) + \\
8(64 + 1) + 9(81 + 1) + 10(100 + 1) \\
\]
Add the terms or the constants which are present in the braces. On adding the terms we have
\[ \Rightarrow 1(2) + 2(5) + 3(10) + 4(15) + 5(26) + 6(37) + 7(50) + 8(65) + 9(82) + 10(101)\]
If the term is in the braces and there is no arithmetic operation then we apply the multiplication arithmetic operation to the terms.
So on multiplying we get
\[ \Rightarrow 2 + 10 + 30 + 60 + 130 + 222 + 350 + 520 + 738 + 1010\]
Between the two terms there is a + symbol. This implies that there we use additional arithmetic operations. Therefore on adding we get
\[ \Rightarrow 3072\]
Hence by the properties of summation we have evaluated the summation.
Therefore \[ \Rightarrow \sum\limits_{i = 1}^{10} {i({i^2} + 1)} = 3072\]
Note: The summation symbol is usually represented by \[\sum\limits_{}^{} {} \]. The summation is as defined as \[\sum\limits_{k = 1}^n {{a_k}} = {a_1} + {a_2} + {a_3} + ... + {a_n}\], this the main property of summation. We obtain the sequence and then by adding the sequence we obtain the value. The sequence is written on some rule.
Recently Updated Pages
If x a + bt + ct2 where x is in meters and t is in class 11 physics CBSE

A car covers the first half distance between two places class 11 physics CBSE

The resultant of two vectors overrightarrow P and overrightarrow class 11 physics CBSE

Find the value of cos 135 class 11 maths CBSE

A mass M is held in place by an applied force F and class 11 physics CBSE

A solution of glucose in water is labelled as 10 dfracwv class 11 chemistry CBSE

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Find the value of the expression given below sin 30circ class 11 maths CBSE

Draw a diagram of nephron and explain its structur class 11 biology CBSE

10 examples of friction in our daily life

Proton was discovered by A Thomson B Rutherford C Chadwick class 11 chemistry CBSE

Bond order ofO2 O2+ O2 and O22 is in order A O2 langle class 11 chemistry CBSE

