What is the upper class limit for the class \[25 - 35\] ?
\[(1)\] \[25\]
\[(2)\] \[35\]
\[(3)\] \[60\]
\[(4)\] \[30\]

Hint: We have to find the upper limit of the given class interval \[25 - 35\] . We solve this question using the concept of class - marks of the intervals . We should also have the knowledge about the formula for calculating the class mark of the intervals . We should also have the knowledge of the bounds about the intervals of the given interval.

Complete step-by-step solution:
The upper limit of any of the given intervals of the class is the number which is the greater number in the given class interval .
Similarly , the Lower limit of any of the given intervals of the class is the number which is the smaller number in the given class interval .
Given :
In the given interval of the class \[25 - 35\] , there are two numbers \[25\] and \[35\] . Now, when comparing the two numbers one can easily conclude that the number which is greater among the two numbers is \[35\] .
Hence , we conclude that the upper class limit of the given class is \[35\] .
Thus , the correct option is \[(2)\] .

Note: Using the concept of the limits of the intervals of the class , we can also calculate the frequency or the class mark of the given interval . As if we would have to find the class mark of the given interval then we would calculate it using the particular formula as given below :
\[class{\text{ }}mark{\text{ }} = {\text{ }}\dfrac{{L.L. + U.L.}}{2}\]
Where \[L.L.\] is the lower limit of the interval and \[U.L.\] is the upper limit of the given interval .
Putting the values of the lower and upper limits in the given formula , we get the value of class mark as :
\[class{\text{ }}mark{\text{ }} = {\text{ }}\dfrac{{25 + 35}}{2}\]
\[class{\text{ }}mark = 30\]