Two cylinders A and B fitted with the pistons contain an equal amount of an ideal diatomic gas at $ 300K $ . Piston A is free to move and piston B is fixed. The same amount of heat is given to the gases in two cylinders. Temperature of the gas in cylinder A increases by $ 30K $ . Then, increase in temperature of the gas in cylinder B is:
( $ \gamma = 1.4 $ for diatomic gas)
(A) $ 36K $
(B) $ 54K $
(C) $ 42K $
(D) $ 24K $
Answer
557.1k+ views
Hint: Given that the two cylinders A and B are fitted with pistons. Also they have diatomic gas. Piston A is free to move which means pressure remains constant and piston B is fixed which means that the volume inside that cylinder remains constant. So using the ratio of the specific heat we can find the increase in temperature.
Complete answer:
Piston A is free to move. That means that the pressure inside that cylinder will be constant, which means the process is isobaric.
Thus for given heat to the system is
$ \therefore \Delta {Q_A} = n{C_p}\Delta {T_A} \ldots \ldots \left( 1 \right) $
Piston B is fixed. This implies that the volume inside the cylinder is constant. This means that the process is isochoric.
Thus for the given heat to the system is
$ \therefore \Delta {Q_B} = n{C_v}\Delta {T_B} \ldots \ldots \left( 2 \right) $
Given in the question is that the same heat is given to both the cylinders. Therefore,
$ \Delta {Q_A} = \Delta {Q_B} $ ……..(3)
Therefore equating (1) and (2)
$ n{C_p}\Delta {T_A} = n{C_v}\Delta {T_B} $ ……… (4)
$ \Delta {T_B} = \left( {\dfrac{{{C_p}}}{{{C_v}}}} \right)\Delta {T_A} $ ………. (5)
The ratio of the specific heat is given as,
$ \gamma = \left( {\dfrac{{{C_p}}}{{{C_v}}}} \right) = 1.4 $ for diatomic gases.
Also, the increase in temperature for cylinder A is given as
$ \Delta {T_A} = 30K $
Substituting both the values in the equation (5),
$ \Delta {T_B} = 1.4 \times 30K $
$ \Delta {T_B} = 42K $
Therefore the correct option is C.
Note:
Note that the specific heat capacity of a body is the amount of heat required to raise the temperature of the body of unit mass from $ {0^0}C $ to $ {1^0}C $ . It is represented by C and its units are usually calories or $ Joule/KgK $ . The specific heat capacity of water at room temperature is higher than most other materials. We use this property of water in our body to maintain constant body temperature.
Complete answer:
Piston A is free to move. That means that the pressure inside that cylinder will be constant, which means the process is isobaric.
Thus for given heat to the system is
$ \therefore \Delta {Q_A} = n{C_p}\Delta {T_A} \ldots \ldots \left( 1 \right) $
Piston B is fixed. This implies that the volume inside the cylinder is constant. This means that the process is isochoric.
Thus for the given heat to the system is
$ \therefore \Delta {Q_B} = n{C_v}\Delta {T_B} \ldots \ldots \left( 2 \right) $
Given in the question is that the same heat is given to both the cylinders. Therefore,
$ \Delta {Q_A} = \Delta {Q_B} $ ……..(3)
Therefore equating (1) and (2)
$ n{C_p}\Delta {T_A} = n{C_v}\Delta {T_B} $ ……… (4)
$ \Delta {T_B} = \left( {\dfrac{{{C_p}}}{{{C_v}}}} \right)\Delta {T_A} $ ………. (5)
The ratio of the specific heat is given as,
$ \gamma = \left( {\dfrac{{{C_p}}}{{{C_v}}}} \right) = 1.4 $ for diatomic gases.
Also, the increase in temperature for cylinder A is given as
$ \Delta {T_A} = 30K $
Substituting both the values in the equation (5),
$ \Delta {T_B} = 1.4 \times 30K $
$ \Delta {T_B} = 42K $
Therefore the correct option is C.
Note:
Note that the specific heat capacity of a body is the amount of heat required to raise the temperature of the body of unit mass from $ {0^0}C $ to $ {1^0}C $ . It is represented by C and its units are usually calories or $ Joule/KgK $ . The specific heat capacity of water at room temperature is higher than most other materials. We use this property of water in our body to maintain constant body temperature.
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