Two absolute scales A and B have triple points of water defined to be $ 200A $ and $ 300B $ . A temperature is measured on these scales $ {T_A} $ and $ {T_B} $ .What is the relation between $ {T_B} $ and $ {T_A} $ ? Given that, the triple point of water as $ 273.16K $ .

Hint: To solve this question we have to know about triple point. We know that, in physics, the temperature at which each of the three periods of issue (strong, fluid, and gas) for a given substance can coincide. Note. The triple point for water is a little over the edge of freezing over, and is utilized to characterize temperature scales.

Complete answer:
We can say, triple points of water on absolute scale A and B are $ 200A $ and $ 300B $ respectively according to the question.
 We know that, the triple point A in Kelvin is equal to $ 273.16K $
Hence we are considering, $ {T_1} = {T_k} $
Or, $ 273.16 = 200A $
Similarly, we can say,
 $ 273.16 = 300B $
By solving these two above equations we will get,
 $ \dfrac{{273.16}}{{200}} \times {T_A} = \dfrac{{273.16}}{{350}} \times {T_B} $
Hence the ratio of the temperatures are,
 $ {T_A}:{T_B} = 4:7 $ .

Note:
We have to know that, in thermodynamics, the triple point of a substance is the temperature and pressing factor at which the three stages ( gas, fluid, and strong) of that substance coincide in thermodynamic harmony. It is that temperature and pressing factor at which the sublimation bend, combination bend and the vaporization bend meet. And also, for most substances the gas–fluid strong triple point is likewise the base temperature at which the fluid can exist. For water, notwithstanding, this isn't correct on the grounds that the dissolving point of customary ice diminishes as an element of pressing factor.