How many times a cell will have to divide mitotically, to form 128 cells?
(A)7
(B)14
(C)28
(D)32

Hint: When a single mitotic division takes place, it produces 2 cells. Similarly, when this cell divides a second time, it produces four cells and this process continues. In this manner, the no of times a cell will have to divide mitotically, to form 128 cells can be calculated.

Complete answer:
The cell will have to divide 7 times mitotically, to form 128 cells. The number of times a cell will have to divide mitotically is calculated by the formula ${ 2 }^{ n }$, where n is the number of times the cell is dividing.

Additional Information: Mitosis is a process where one cell divides into two identical daughter cells (cell division). During the mitosis, one cell divides once to make two identical cells.
. The process of mitosis is split into stages like the completion of 1 set of activities and therefore the start of subsequent. These stages are named the prophase, prometaphase, metaphase, anaphase, and telophase. During the process of mitosis, it was seen that the chromosome, which was already gone under duplication, condensed and fixed to The spindle fibers that pull one copy of every chromosome to opposite sides of the cell. The result's two genetically identical daughter nuclei. The various phases of mitosis are often visualized in real-time, using live-cell imaging. Some errors during mitosis can induce apoptosis (programmed cell death) or cause mutations. Certain sorts of cancer can arise from such mutations.
So, the correct answer is ‘7’.

Note: The major purpose of mitosis is for growth and to exchange worn-out cells.
If not corrected in time, mistakes made during mitosis may result in changes within the DNA which will potentially cause genetic disorders.