Three consecutive predecessors of 70010 are
A. 70009, 70008, 7007
B. 70009, 70008, 70010
C. 70009, 70008, 70007
D. 70009

Hint- In order to find the consecutive predecessors of the given number subtract 3 smallest natural numbers one by one separately and enlist them.

Complete Step-by-Step solution:
In order to find the three consecutive predecessors of 70010.
We will subtract 1, 2 and 3 from the given number to find consecutive predecessors.
First predecessor
$ \Rightarrow 70010 - 1 = 70009$
Second predecessor
$ \Rightarrow 70010 - 2 = 70008$
Third predecessor
$ \Rightarrow 70010 - 3 = 70007$
Hence, the three predecessors of 70010 are 70009, 70008 and 70007.
So, option C is the correct option.

Note- Predecessor refers to the previous term of a particular term while the successor refers to the next term of a particular term. In order to find the successor of a whole number, one must add one to the particular given number. In order to find a predecessor, one must subtract one from the particular given number. To find the given number of predecessors as in above case subtract as many smallest natural no as asked.