Three coins are tossed simultaneously 200 times with the following frequencies of different outcomes:

Outcome	3 heads	2 heads	1 head	0 head
Frequency	23	72	77	28

Hint: To find out the probability of a desired outcome we are provided with the formulae
P(A) =n(E)/n(S)
Where,
P(A) = Probability of an event
n(E) = Number of desired outcome
n(S) = Total number of outcomes


Complete step by step explanation:
1. Total number of times three coins are tossed simultaneously = Total number of outcomes
i.e. n(S) = 200
2. Number of times the coins are tossed and 2 heads come up = Number of desired outcomes
i.e. n(E) = 72
3. If P(A) to be the probability of 2 heads coming up after tossing 3 coins simultaneously
Using the formulae P(A) = n(E)/n(S)
Substituting the values of n(E) and n(S) from step 1 and step 2, we get
P(A) = $\dfrac{{72}}{{200}}$
P(A) Probability of getting 2 heads when 3 coins are tossed simultaneously = $\dfrac{{72}}{{200}}$
=$\dfrac{{9}}{{25}}$

Note: It has to be noted that probability of any event will be either 0 or 1 or between 0 and 1.If the value obtained is going out of this range,it is an indication that the calculation is wrong