The length of a string between a kite and a point on the ground is 90 metres. If the string makes an angle $\theta $ with the ground level such that $\tan \theta =\dfrac{15}{8}$, how high is the kite? Assume that there is no slack in the string.

Hint:Assume that the point on the ground is A and the kite is at point C and B is the point vertically below the kite on the ground. Observe that $\Delta ABC$ is a right-angled triangle, right-angled at B. As $\tan \theta =\dfrac{15}{8}$, assume that $BC=15x,AB=8x$. Use Pythagoras Theorem to calculate the length of all sides of the triangle and thus, the length of side BC.

Complete step-by-step answer:
We know that the length of string between a kite and a point on the ground is 90m and the string makes an angle $\theta $ with the ground such that $\tan \theta =\dfrac{15}{8}$. We have to find the height of the kite.
Let’s assume that the point on the ground is A and the kite is at point C and B is the point vertically below the kite on the ground. We observe that $\Delta ABC$ is a right-angled triangle, right-angled at B.
As $\tan \theta =\dfrac{15}{8}$assume that $BC=15x,AB=8x$, as shown in the figure.

We know that Pythagoras Theorem states that in a right-angled triangle, the sum of the square of two perpendicular sides is equal to the square of the third side. So, we have $A{{B}^{2}}+B{{C}^{2}}=A{{C}^{2}}$.
Substituting $AB=8x,BC=15x,AC=90$ in the above formula, we have ${{\left( 8x \right)}^{2}}+{{\left( 15x \right)}^{2}}={{\left( 90 \right)}^{2}}$.
Simplifying the above equation, we have $64{{x}^{2}}+225{{x}^{2}}=8100\Rightarrow 289{{x}^{2}}=8100$.
Rearranging the terms of the above equation and taking the square root, we have ${{x}^{2}}=\dfrac{8100}{289}\Rightarrow x=\sqrt{\dfrac{8100}{289}}=\dfrac{90}{17}$.
So, the height of the kite is $BC=15\left( \dfrac{90}{17} \right)=79.41m$.
Hence, the height of the kite is 79.41 metres.

Note: We have to use Pythagoras Theorem to calculate the length of the sides of the triangle. One must know that tangent of any angle is the ratio of the length of the perpendicular and the base. We can also find the value of the angle $\theta $ as $\theta ={{\tan }^{-1}}\left( \dfrac{15}{8} \right)$.