The gravitational intensity is denoted as
$\begin{align}
  & A. g \\
 & B. G \\
 & C. E \\
 & D. None \\
\end{align}$

Hint: Gravitational intensity is explained as the measurement of the force that is experienced by a unit mass in the given gravitational field. It is in the units of $NK{{g}^{-1}}$. It is basically a vector quantity.

Complete step by step answer:
First of all let us take a look at what the gravitational intensity is. Gravitational intensity is explained as the measurement of the force that is experienced by a unit mass in the given gravitational field. It is in the unit of $NK{{g}^{-1}}$ . It is basically a vector quantity. A measure of a vector quantity which is in connection to the condition that at any of the points in the gravitational influence exerts a gravitational force upon a unit mass placed at a point. It is denoted as $g$. And the formula of the gravitational field intensity is given by,
$g=\dfrac{GM}{{{R}^{2}}}$
Where $G$ is the gravitational constant, $M$ is the mass of the object which is providing this field of intensity and $R$ is the radius of the object with gravitational field of intensity.

So, the correct answer is “Option A”.

Note: The gravitational potential at a location is similar to the work or the energy transferred per unit mass that would be needed to make a movement for an object to a specific location from a fixed reference location. It is similar to the electric potential which is based on charge as here it is based on mass. The point at which the potential is zero is taken as the reference point. And by convention infinitely at a larger distance away from any mass, resulting in a negative potential at any certain distance.