The equivalent capacitance between x and y is?
(A) $5/6\mu F$
(B) $7/6\mu F$
(C) $8/3\mu F$
(D) $1\mu F$

Hint:We need to find the equivalent capacitance of the circuit, there are four capacitances present in the circuit. We can make use of laws of series and parallel combination to find the equivalent capacitance. We have to assume that the current enters into the circuit either through x or y. Then we can see at which point the current divides or not. If the current in the two capacitors are the same then they are said to be in parallel combination.

Complete step by step answer:
We can see that the capacitance of $1\mu F\And 1\mu F$are in parallel combination, so their equivalent capacitance will be$1+1=2\mu F$. Now the circuit looks like:

Now the three capacitances remaining in the circuit are $1\mu F,2\mu F\And 3\mu F$. The capacitors of $1\mu F$and $2\mu F$are in series combination and their equivalent is in parallel with the third one.
Thus, equivalent capacitance of the circuit is:
$\Rightarrow \dfrac{1}{C}=\dfrac{1}{2}+1$
$\Rightarrow \dfrac{1}{C}=\dfrac{1+2}{2}$
$\Rightarrow \dfrac{1}{C}=\dfrac{3}{2}$
$\Rightarrow C=\dfrac{2}{3}\mu F$and this is in parallel with $2\mu F$
Therefore,
$\Rightarrow {{C}_{net}}=2+\dfrac{2}{3}$
$\Rightarrow {{C}_{net}}=\dfrac{6+2}{3}$
$\therefore {{C}_{net}}=\dfrac{8}{3}\mu F$

So, the correct option is C.

Note: Apart from parallel plate capacitors, there exist a class of capacitors which are cylindrical in shape. Capacitors are added in series in the manner the resistances are added in parallel combination and capacitors are added in parallel in the manner resistances are added in series. Also, we have not converted the capacitance into Farads, as there was no such demand in the question.Also, capacitors have the ability to store the charge and when the capacitor is fully charged then no current flows through it.