The distance between two particles in a wave motion vibrating out of phase of \[\pi \] radians is:
A. \[\lambda /4\]
B. \[\lambda /2\]
C. \[3\lambda /4\]
D. \[\lambda \]
Answer
633k+ views
Hint:Use the formula for phase difference between the two particles in the wave motion. This formula gives the relation between the phase difference between the two particles, path difference or distance between the two particles and wavelength of the wave. Substitute the given value of phase difference in this equation and calculate the distance between the two particles.
Formula used:
The phase difference \[\Delta \phi \] between the two particles in the wave motion is given by \[\Delta \phi = \dfrac{{2\pi \Delta x}}{\lambda }\] …… (1)
Here, \[\Delta x\] is the path difference between the particles and \[\lambda \] is the wavelength of the wave.
Complete step by step answer:
We have given that the phase difference between the two particles vibrating out of phase is \[\pi \] radians.
\[\Delta \phi = \pi \,{\text{radian}}\]
We have asked to determine the distance between these two particles in the wave motion.
Rearrange the equation (1) for path difference \[\Delta x\] between the particles.
\[\Delta x = \dfrac{{\Delta \phi \lambda }}{{2\pi }}\]
Substitute \[\pi \,{\text{radian}}\] for \[\Delta \phi \] in the above equation.
\[\Delta x = \dfrac{{\left( {\pi \,{\text{radian}}} \right)\lambda }}{{2\pi }}\]
\[ \Rightarrow \Delta x = \dfrac{{\pi \lambda }}{{2\pi }}\]
\[ \Rightarrow \Delta x = \dfrac{\lambda }{2}\]
Thus, the path difference between the two particles in the wave motion is \[\dfrac{\lambda }{2}\].
Therefore, the distance between the two particles in the wave motion which are out of phase is \[\dfrac{\lambda }{2}\].
Hence, the correct option is B.
Additional information:
Two particles on a wave are said to be in phase if they have phase difference of zero.
Two particles on a wave are said to be out of phase if they have a non-zero phase difference.
Note:The students may think that the path difference between the two particles in the wave motion cannot be the distance between the two particles in the wave motion. But the students should keep in mind that the path difference between these two particles in the wave motion here is the distance between the two particles on the wave in the wave motion.
Formula used:
The phase difference \[\Delta \phi \] between the two particles in the wave motion is given by \[\Delta \phi = \dfrac{{2\pi \Delta x}}{\lambda }\] …… (1)
Here, \[\Delta x\] is the path difference between the particles and \[\lambda \] is the wavelength of the wave.
Complete step by step answer:
We have given that the phase difference between the two particles vibrating out of phase is \[\pi \] radians.
\[\Delta \phi = \pi \,{\text{radian}}\]
We have asked to determine the distance between these two particles in the wave motion.
Rearrange the equation (1) for path difference \[\Delta x\] between the particles.
\[\Delta x = \dfrac{{\Delta \phi \lambda }}{{2\pi }}\]
Substitute \[\pi \,{\text{radian}}\] for \[\Delta \phi \] in the above equation.
\[\Delta x = \dfrac{{\left( {\pi \,{\text{radian}}} \right)\lambda }}{{2\pi }}\]
\[ \Rightarrow \Delta x = \dfrac{{\pi \lambda }}{{2\pi }}\]
\[ \Rightarrow \Delta x = \dfrac{\lambda }{2}\]
Thus, the path difference between the two particles in the wave motion is \[\dfrac{\lambda }{2}\].
Therefore, the distance between the two particles in the wave motion which are out of phase is \[\dfrac{\lambda }{2}\].
Hence, the correct option is B.
Additional information:
Two particles on a wave are said to be in phase if they have phase difference of zero.
Two particles on a wave are said to be out of phase if they have a non-zero phase difference.
Note:The students may think that the path difference between the two particles in the wave motion cannot be the distance between the two particles in the wave motion. But the students should keep in mind that the path difference between these two particles in the wave motion here is the distance between the two particles on the wave in the wave motion.
Recently Updated Pages
If x a + bt + ct2 where x is in meters and t is in class 11 physics CBSE

A car covers the first half distance between two places class 11 physics CBSE

The resultant of two vectors overrightarrow P and overrightarrow class 11 physics CBSE

Find the value of cos 135 class 11 maths CBSE

A mass M is held in place by an applied force F and class 11 physics CBSE

A solution of glucose in water is labelled as 10 dfracwv class 11 chemistry CBSE

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Find the value of the expression given below sin 30circ class 11 maths CBSE

Draw a diagram of nephron and explain its structur class 11 biology CBSE

10 examples of friction in our daily life

Proton was discovered by A Thomson B Rutherford C Chadwick class 11 chemistry CBSE

Bond order ofO2 O2+ O2 and O22 is in order A O2 langle class 11 chemistry CBSE

