The difference between C.I. and S.I. on Rs.7500 for two years is Rs.12 at the same rate of interest per annum. Find the rate of interest.
Answer
670.5k+ views
Hint – To find the rate of interest, we take in all the given data in the question which are the principal amount, time period, difference between compound and simple interest and the rate of interest is the same for both of them. We substitute this data in the formulae of simple interest and compound interest to get the answer.
Complete step-by-step answer:
Given data,
Principle P = 7500/-
Rate of interest is same, let it be R
Difference between C.I and S.I = 12/-
Time = 2 years
We know simple interest is given by the formula,
${\text{S}}{\text{.I = }}\dfrac{{{\text{PRT}}}}{{100}}$, where P is the principle, R is the rate of interest and T is the time period.
Therefore the Simple interest in our case is,
${\text{S}}{\text{.I = }}\dfrac{{7500 \times {\text{R}} \times {\text{2}}}}{{100}} = 150{\text{R}}$
We know the compound interest is given by the formula,
${\text{C}}{\text{.I = P}}{\left( {1 + \dfrac{{\text{x}}}{{100}}} \right)^2} - {\text{P}}$, where P is the principle, x is the rate of interest.
Here according to the question rate of interest is R, i.e. x = R therefore the Compound interest in our case is,
${\text{C}}{\text{.I = P}}{\left( {1 + \dfrac{{\text{R}}}{{100}}} \right)^2} - {\text{P}}$
$
{\text{C}}{\text{.I = 7500}}\left( {1 + \dfrac{{{{\text{R}}^2}}}{{10000}} + \dfrac{{2{\text{R}}}}{{100}} - 1} \right) \\
{\text{C}}{\text{.I = }}\dfrac{{{\text{3}}{{\text{R}}^2}}}{4} + 150{\text{R}} \\
$
Given the difference between Compound Interest and Simple Interest = Rs.12
$
\Rightarrow \dfrac{{{\text{3}}{{\text{R}}^2}}}{4} + 150{\text{R}} - 150{\text{R = 12}} \\
\Rightarrow \dfrac{{{\text{3}}{{\text{R}}^2}}}{4} = 12 \\
\Rightarrow {{\text{R}}^2} = 12 \times \dfrac{4}{3} \\
\Rightarrow {\text{R = 4% }} \\
$
Hence the rate of interest is 4%.
Note – In order to solve this type of question the key is to know the definitions and formula of compound interest and simple interest. Here we were able to get both terms into a single variable because the rate of interest is the same.
Compound Interest is calculated by adding the interest to the principal amount after a specific time period. Therefore the principle keeps increasing over time.
Simple Interest is calculated by only counting interest on the actual amount irrespective of the duration of the loan taken. Principle is always constant.
An expansion of the form is given by: ${\left( {{\text{a + b}}} \right)^2} = {{\text{a}}^2}{\text{ + }}{{\text{b}}^2}{\text{ + 2ab}}$.
Complete step-by-step answer:
Given data,
Principle P = 7500/-
Rate of interest is same, let it be R
Difference between C.I and S.I = 12/-
Time = 2 years
We know simple interest is given by the formula,
${\text{S}}{\text{.I = }}\dfrac{{{\text{PRT}}}}{{100}}$, where P is the principle, R is the rate of interest and T is the time period.
Therefore the Simple interest in our case is,
${\text{S}}{\text{.I = }}\dfrac{{7500 \times {\text{R}} \times {\text{2}}}}{{100}} = 150{\text{R}}$
We know the compound interest is given by the formula,
${\text{C}}{\text{.I = P}}{\left( {1 + \dfrac{{\text{x}}}{{100}}} \right)^2} - {\text{P}}$, where P is the principle, x is the rate of interest.
Here according to the question rate of interest is R, i.e. x = R therefore the Compound interest in our case is,
${\text{C}}{\text{.I = P}}{\left( {1 + \dfrac{{\text{R}}}{{100}}} \right)^2} - {\text{P}}$
$
{\text{C}}{\text{.I = 7500}}\left( {1 + \dfrac{{{{\text{R}}^2}}}{{10000}} + \dfrac{{2{\text{R}}}}{{100}} - 1} \right) \\
{\text{C}}{\text{.I = }}\dfrac{{{\text{3}}{{\text{R}}^2}}}{4} + 150{\text{R}} \\
$
Given the difference between Compound Interest and Simple Interest = Rs.12
$
\Rightarrow \dfrac{{{\text{3}}{{\text{R}}^2}}}{4} + 150{\text{R}} - 150{\text{R = 12}} \\
\Rightarrow \dfrac{{{\text{3}}{{\text{R}}^2}}}{4} = 12 \\
\Rightarrow {{\text{R}}^2} = 12 \times \dfrac{4}{3} \\
\Rightarrow {\text{R = 4% }} \\
$
Hence the rate of interest is 4%.
Note – In order to solve this type of question the key is to know the definitions and formula of compound interest and simple interest. Here we were able to get both terms into a single variable because the rate of interest is the same.
Compound Interest is calculated by adding the interest to the principal amount after a specific time period. Therefore the principle keeps increasing over time.
Simple Interest is calculated by only counting interest on the actual amount irrespective of the duration of the loan taken. Principle is always constant.
An expansion of the form is given by: ${\left( {{\text{a + b}}} \right)^2} = {{\text{a}}^2}{\text{ + }}{{\text{b}}^2}{\text{ + 2ab}}$.
Recently Updated Pages
You are the head boyhead girl Write a notice informing class 7 english CBSE

The image formed by a plane mirror is always laterally class 7 physics CBSE

When phenolphthalein is added toNaOH the colour of class 7 chemistry CBSE

Find the least number which when divided by 15 leaves class 7 maths CBSE

Show that one and only one out of n n + 2n or n + -class-7-maths-CBSE

During heavy exercise we get cramps in the legs due class 7 biology CBSE

Trending doubts
Full Form of IASDMIPSIFSIRSPOLICE class 7 social science CBSE

List of coprime numbers from 1 to 100 class 7 maths CBSE

The plural of Chief is Chieves A True B False class 7 english CBSE

The founder of Jainism was A Rishabhadev B Neminath class 7 social science CBSE

Collective noun a of sailors class 7 english CBSE

Differentiate between weather and climate How do they class 7 social science CBSE


