The bond order of $ {{B}_{2}} $ molecule is

Hint :We know that the bond order is the number of bonds formed between the atoms interacting with each other. It is the measure of the stability of the molecule. The stability of the molecule also depends on the type of bonds. The electronic configuration of the atoms determines the bond order.

Complete Step By Step Answer:
We know that molecular orbital diagrams are used to determine the bonding in a diatomic molecule. The molecular orbital diagrams are used to predict the magnetic properties of a molecule. Molecular orbital diagrams help in determining the bond order of the molecule. We know that molecular orbital theory explains the formation of molecules.
According to molecular orbital theory, the atomic orbitals having comparable energy overlap and result in the formation of the same number of molecular orbitals. The molecular orbitals having the same sign combine and give bonding molecular orbitals. The average bond order formula considers the number of electrons on the bonding and the antibonding orbitals. It is defined as half of the difference between them. The bond order shows the number of chemical bonds present between a pair of atoms. The Bond Order Formula can be defined as half of the difference between the number of electrons in bonding orbitals and antibonding orbitals.
Where, $ {{N}_{b}}~= $ Number of bonding electrons and $ {{N}_{a}}~= $ Number of antibonding electrons
Bond order of $ ~{{B}_{2}}~ $ molecule and the atomic number of Boron $ \left( B \right) $ is $ 5, $ the electronic configuration of Boron is, $ B\left( Z=5 \right)=1{{s}^{2}}~2{{s}^{2~}}2{{p}^{1}} $
 $ Bond\text{ }order=\dfrac{1}{2}\left[ {{N}_{b}}~\text{ }{{N}_{a}} \right]=1 $ .

Note :
Remember that there is a well-established bond order formula to calculate bond order. It is important to study the formula to find bond order to look into the structure of different compounds and calculate their stability.