Solve the multiplication \[271\times 5\] .

Hint: We have two numbers. One of the numbers is 271 which is a 3-digits number and the other number is 5 which is a unit digit. Now, multiply the one's digit of 271 by the one's digit of 5. Now, multiply the tens digit of 271 by 5. The number is greater than 0. So, we have to write the ones digit and put the tens digit as carry on the hundreds digit of 271. Now, multiply the hundreds digit of 271 by the one's digit of 5 and then add the carry.

Complete step-by-step answer:

According to the question, it is asked to find the multiplication of two numbers and the numbers are 271 and 5.
We have two numbers. One of the numbers is 271 which is a 3-digits number and the other number is 5 which is a unit digit.
Now, we have to write these two numbers one below the other according to the places of their digits. We have to put the bigger number on top and a multiplication sign on the left. Draw a line below the numbers.
\[\begin{align}
  & 271 \\
 & \underline{\times \,\,\,\,5} \\
 & \\
\end{align}\]
Multiplying the one's digit of the top number by the one's digit of the bottom number, we get
\[\begin{align}
  & 271 \\
 & \underline{\times \,\,\,\,5} \\
 & \,\,\,\,\,\,\,5 \\
\end{align}\]
Now, multiplying the tens digit of the top number by the one's digit of the bottom number, we get
\[\begin{align}
  & 3 \\
 & 271 \\
 & \underline{\times \,\,\,\,5} \\
 & \,\,\,5\,5 \\
\end{align}\]
On multiplication, we get 35 so, we have to write the unit digit of 35 at the tens digit. The number 35 is greater than 9, so we have to put the tens digit of 35 as carry on the hundred’s digit of 271.
Now, multiplying the hundred’s digit of 271 by the one's digit of the bottom and then adding the carry, we get
\[\begin{align}
  & \,\,\,\,\,\,\,\,\,\,\,2\,7\,1 \\
 & \underline{\times \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,5} \\
 & (10+3)\,5\,5 \\
\end{align}\]
On multiplication, we get 10 and then add the carry. Here, the carry is 3. After adding we get (10+3=13).
\[\begin{align}
  & \,\,2\,7\,1 \\
 & \underline{\times \,\,\,\,\,\,5} \\
 & 13\,5\,5 \\
\end{align}\]
Hence, the multiplication of 271 by 5 is 1355.

Note: In this question, after the multiplication of the tens digit with the one's digit, one might write the number and ignore the carry. Like,
\[\begin{align}
  & 271 \\
 & \underline{\times \,\,\,\,5} \\
 & \,\,35\,5 \\
\end{align}\]
This is wrong, If we get the multiplication greater than 9 then we have to put the tens digit as carry on the next digit of the top number.