How do you solve the linear equation $-4y+16=4$?

Hint: To solve the given equation first we will rearrange the terms. We will keep constant terms on one side and arrange the variable terms on the other side. Then we will simplify the obtained equation to get the desired answer.

Complete step-by-step solution:
We have been given an equation $-4y+16=4$.
We have to solve the given equation.
To solve the given equation first we will rearrange the variable and constant terms given in the equation.
Now, we will shift the constant terms at the RHS then we will get
$\Rightarrow -4y=4-16$
Now, simplifying the obtained equation we will get
$\Rightarrow -4y=-12$
Now, dividing the above obtained equation by $-4$ we will get
$\Rightarrow \dfrac{-4y}{-4}=\dfrac{-12}{-4}$
Now, simplifying the obtained equation we will get
$\Rightarrow y=3$
Hence on solving the given equation we will get the value of y as 3.

Note: The given equation is a linear equation in one variable as there is only one unknown variable. The possibility of mistake in this type of question is calculation mistake. Be careful while doing calculations and while shifting the terms from LHS to RHS or vice-versa. We can also verify the answer by substituting the obtained value in the given equation.
Substituting the value of y we will get
$\Rightarrow -4\times 3+16=4$
Now, simplifying the above obtained equation we will get
$\begin{align}
  & \Rightarrow -12+16=4 \\
 & \Rightarrow 4=4 \\
\end{align}$
As we get LHS=RHS, hence the obtained solution is correct.