Solve the given equation: \[3x+8=-5x+4\]

- Hint: Here the given problem is \[3x+8=-5x+4\].We have to find the value of x by equating and moving the terms from left hand side to right hand side. Moving the common terms to one side and solving.

Complete step-by-step solution -

Moving the x terms to the left hand side and remaining numericals to the right hand side and then performing the mathematical operations.

The given problem is \[3x+8=-5x+4\].
Considering L.H.S as \[3x+8\] and R.H.S as \[-5x+4\].
Now moving the x terms to the left hand side and remaining numericals to the right hand side. The equation now appears as \[3x+5x=4-8\]
Now x is taken as common in the left hand side, the equation now appears as
\[x\left( 3+5 \right)=4-8\]
Adding all the terms in the right hand side, The equation now appears as \[8x=-4\].
Dividing the value 8 on both sides we get the required equation as \[\dfrac{8x}{8}=\dfrac{-4}{8}\]
In left hand side 8 gets cancelled in both numerator and denominator, , the equation now appears as \[x=\dfrac{-4}{8}\]
In right hand side dividing -4 with 8 we get the value of x as \[x=\dfrac{-1}{2}\]
Therefore the value of x is -1.5.
If we put the value of x in both L.H.S and R.H.S we get both the terms equal.
Hence the value of x is -1.5

Note: This is a direct problem where the value of x can be found by moving the terms from L.H.S to R.H.S and performing mathematical expressions. To check placing the value of x in the above equation gives L.H.S = R.H.S.