Solve the given equation. \[16=4+3(t+2).\]

Hint: Given is an algebraic expression. Rearrange the terms in question. Make it undergo algebraic operations like subtraction and division to get the value of t.

Complete step-by-step answer:

Given is an algebraic expression, \[16=4+3(t+2)\], with variable ‘t’.
An algebraic expression is built up from integer, constants, variables, and algebraic operations like addition, subtraction, multiplication, division and exponentiation by an exponent.
We have been given an expression with a variable ‘t’. So we need to find the value of t from the given expression.
\[16=4+3(t+2).\]
Let us open the brackets on RHS of expression. We get,
\[\begin{align}
  & 16=4+3t+6 \\
 & 16=10+3t \\
\end{align}\]
Take 10 from RHS to LHS. It becomes (-10).
\[\begin{align}
  & 16-10=3t \\
 & 6=3t. \\
\end{align}\]
Now use the algebraic division, take 3 from the numerator of RHS to the denominator of LHS.
\[\dfrac{6}{3}=t\Rightarrow 2=t.\]
Hence we got the value of t = 2 by solving the expression.

Note: In this question, we have been given only one variable ‘t’. So solving expressions like these, we get the value of t. If we have been given 2 variables then we would require 2 equations to solve the equations.