Solve the following equation $4+5\left( p-1 \right)=34$ .

- Hint:First write the single degree equation with left hand side and right-hand side. Find the coefficient of variable on both sides of equations. Subtract the term with coefficient of variable on right hand side. Now, there will be no variable on the right hand side. Now similarly, find the constants value of the left-hand side on both sides of the equation. Now you get an equation with variable terms on the left hand side and constant term on the right hand side. Now, find the coefficient term of the variable on the left hand side. Divide with this coefficient on both the sides of the equation. Now you have only the variable with coefficient 1 on the left hand side and some constant on the right hand side. So, this constant will be your result.

Complete step-by-step solution -

Linear Polynomial: If the degree of polynomial is 1 then they are called linear polynomials. For example: \[x+1,x+2,x+3\] .
Degree of polynomial: The highest power of a variable in a polynomial is called its degree. For example: \[{{x}^{2}}+4x+2\] has degree of 2, \[x+1\] : degree of 1, \[{{x}^{3}}+1\] : degree of 3, 2 is a polynomial of degree 0.
Given expression in the question which we need to solve:
$\Rightarrow 4+5\left( p-1 \right)=34$
To remove the parentheses, we must multiply the 5 inside bracket:
$\Rightarrow 4+5p-5=34$
Coefficient of the variable on the right hand side is 0.
So, the variable is only on the left hand side. Now check the constants on left hand side, right hand side are: - $-1,34$
By adding 1 on both sides of equation, we get
$\Rightarrow 5p+4-5+1=34+1$
By simplifying the above equation, we get the equation:
$\Rightarrow 5p=35$
As the coefficient of variable on left hand side is 5, do as follow:
By dividing with 5 on both sides of equation, we get:
$\Rightarrow \dfrac{5p}{5}=\dfrac{35}{5}$
By cancelling the common terms of equation, we get value of p as:
$p=7$
Therefore, the value of p satisfying the given condition is 7.

Note: While removing parentheses students forget to multiply the constant term and write $-1$ but it must be $-5$ . Be careful. Alternate method is to keep all the variable terms to the right hand side and constants to left hand side anyways, you get the same result. What hand side if not you may lead to wrong answer.never you apply an operation on the left hand side, don’t forget to apply the same on rig