Solve the equation: \[3x = 24\]?

Hint: Here in this question, we have to solve the given equation and it is in the form of an algebraic equation having a variable x. Solving this equation, we have to find the unknown value x by using the basic arithmetic operation like multiplication and division we find the value of x.

Complete step-by-step solution:
The given equation is an algebraic equation. The algebraic equation is a combination of variable and constant and which has an equal sign. So we use multiplication and division or arithmetic operations and solve for further
Now consider the given equation
\[ \Rightarrow \,\,3x = 24\]
Now divide the above equation by 3, we get
\[ \Rightarrow x = \dfrac{{24}}{3}\]
Now, we simplify the above fraction to get the value of variable x.
The factors of 24 are 1, 2, 3, 4, 6, 8, 12 and 24
The factors of 3 are 1 and 3
Therefore, using the common factor the numerator of fraction i.e., 27 can be written as \[24 = 3 \times 8\], then the fraction becomes
\[ \Rightarrow x = \dfrac{{3 \times 8}}{3}\]
On cancelling the like terms i.e., 3 on both numerator and denominator, we get
 \[ \Rightarrow x = 8\]
Hence, it’s a required solution.
We can also verify the given question by substituting the value of x.
Consider \[3x = 24\]. Substitute the value of x as -8, so we have
\[ \Rightarrow 3\left( 8 \right) = 24\]
On simplification we get
\[ \Rightarrow 24 = 24\]
Hence LHS is equal to RHS.

Note: If the algebraic expression contains only one unknown, we determine the value by using simple multiplication and division. The function contains a fraction then there is no change in solving the algebraic expression. The tables of multiplication should be known to solve these kinds of problems.