Solve the algebraic equation: \[5x+\dfrac{7}{2}=\dfrac{3}{2}x-14\].
Answer
682.8k+ views
Hint: Rearrange the given expression, apply the basic algebraic operations addition and subtraction and solve the equation and get the value of x.
Complete step-by-step answer:
The given expression is an algebraic expression. It is built up from integer constants, variables and the algebraic operations like addition, subtraction, multiplication, division etc.
We have been given an algebraic expression \[5x+\dfrac{7}{2}=\dfrac{3}{2}x-14\].
The only variable that has been used is x. Thus we need to solve this equation and find the value of x.
\[5x+\dfrac{7}{2}=\dfrac{3}{2}x-14\]
Let us first rearrange the above expression.
\[5x+\dfrac{3}{2}x=\dfrac{-7}{2}-14\]
Take LCM on both sides, i.e. take LCM of LHS and RHS and simply the expression obtained.
\[\begin{align}
& \dfrac{\left( 2\times 5 \right)x-3x}{2}=\dfrac{-7-14\times 2}{2} \\
& \dfrac{10x-3x}{2}=\dfrac{-7-28}{2} \\
& \therefore \dfrac{7x}{2}=\dfrac{-35}{2} \\
\end{align}\]
Cancel out 2 in both the denominators of LHS and RHS.
\[\begin{align}
& 7x=-35 \\
& \therefore x=\dfrac{-35}{7}=-5 \\
\end{align}\]
Thus we got the value of x = -5.
Note: For solving an expression with one variable only one equation is needed. If there were 2 variables namely x and y, then we require 2 equations to get the x and y. Similarly if there were 3 variables then we will need 3 equations to solve the same.
Complete step-by-step answer:
The given expression is an algebraic expression. It is built up from integer constants, variables and the algebraic operations like addition, subtraction, multiplication, division etc.
We have been given an algebraic expression \[5x+\dfrac{7}{2}=\dfrac{3}{2}x-14\].
The only variable that has been used is x. Thus we need to solve this equation and find the value of x.
\[5x+\dfrac{7}{2}=\dfrac{3}{2}x-14\]
Let us first rearrange the above expression.
\[5x+\dfrac{3}{2}x=\dfrac{-7}{2}-14\]
Take LCM on both sides, i.e. take LCM of LHS and RHS and simply the expression obtained.
\[\begin{align}
& \dfrac{\left( 2\times 5 \right)x-3x}{2}=\dfrac{-7-14\times 2}{2} \\
& \dfrac{10x-3x}{2}=\dfrac{-7-28}{2} \\
& \therefore \dfrac{7x}{2}=\dfrac{-35}{2} \\
\end{align}\]
Cancel out 2 in both the denominators of LHS and RHS.
\[\begin{align}
& 7x=-35 \\
& \therefore x=\dfrac{-35}{7}=-5 \\
\end{align}\]
Thus we got the value of x = -5.
Note: For solving an expression with one variable only one equation is needed. If there were 2 variables namely x and y, then we require 2 equations to get the x and y. Similarly if there were 3 variables then we will need 3 equations to solve the same.
Recently Updated Pages
Write any three differences between metals and nonmetals class 10 social science CBSE

Amit standing on a horizontal plane finds a bird flying class 10 maths CBSE

Two circles of radii 5 cm and 3 cm intersect at two class 10 maths CBSE

Solve the following i John and Jivanti together have class 10 maths CBSE

What is the relation between orthocenter circumcentre class 10 maths CBSE

Two plane mirrors are inclined at 70circ A ray incident class 10 physics CBSE

Trending doubts
Explain the Treaty of Vienna of 1815 class 10 social science CBSE

Which country is known as "The land of Fire and Ice"?

1 GB equals how many MB?

10 examples of evaporation in daily life with explanations

What is the full form of POSCO class 10 social science CBSE

Make a sketch of the human nerve cell What function class 10 biology CBSE

