How do you solve for the given variable, the equation is \[(c + 3) - 2c - (1 - 3c) = 2\]?

Hint:The question is designed for a variable say “c” and after some rearrangement we can get the value of that variable, these kind of question needed to be solved directly using simple math, no need of doing any extra work that is using unnecessarily any property of something. Variables and constants are needed to be separated alone on opposite sides of the equal to sign.

Complete step by step solution:
The given question \[(c + 3) - 2c - (1 - 3c) = 2\]
Needs to find the value of the given variable “c” from the equation given:
Here on solving the given equation we get:
\[
\Rightarrow (c + 3) - 2c - (1 - 3c) = 2 \\
\Rightarrow c + 3 - 2c - 1 + 3c = 2 \\
\Rightarrow 4c - 2c + 2 = 2 \\
\Rightarrow 2c = 2 - 2 = 0 \\
\Rightarrow c = \dfrac{0}{2} \\
\Rightarrow c = 0 \\
\]
Here we got the value of the variable we are asked for and the answer is zero.

Additional Information: In solving this kind of question you have to be very clear with the brackets that is when the bracket opens with the negative sign then that sign multiplies with every term of the bracket, and rest the question needs only simple simplification that is arrange the variable term aside and constant term aside to get the answer.

Note: This question can be solved only by using simple steps needed to be solved for an linear algebraic equation. Here we can check for the value of the variable, by putting the value of the variable in the initial equation given in the question and we can see that the equation satisfies the value of the variable we obtained that is zero.