How do you solve for “do” in\[\dfrac{{hi}}{{ho}} = - \dfrac{{di}}{{do}}\]?
Answer
621.6k+ views
Hint: For getting the value of a variable in this kind of fraction form, you just need to simplify the fraction, if simplification is possible with the fraction term then first simplify it and then cross multiply and find the solution of the variable, if simplification is not possible then just simply put every term in one side of equation and the variable on the other side to get the solution.
Complete step by step solution:
The given question is to simplify the fraction equation
\[\dfrac{{hi}}{{ho}} = - \dfrac{{di}}{{do}}\]
And to find the value of “do”
Assuming that the given terms in the fraction part are solely independent, that is the given variables can’t be reduced by cancelling the similar letters in denominator and numerator we get:
\[
\Rightarrow \dfrac{{hi}}{{ho}} = - \dfrac{{di}}{{do}} \\
\Rightarrow do \times \dfrac{{hi}}{{ho}} = - di \\
\Rightarrow do = - di \times \dfrac{{ho}}{{hi}} \\
\]
This is our final solution for the variable asked in the question.
Additional Information:Here you can also assume the terms as some other variable to get no confusion with the cross multiplication and getting the solution of the equation, but since there are only two –two variables written in the terms of fraction so you can solve directly also.
Note:To get solution of such question you need to clear with the cross multiplication rule, that is when you multiply the denominator of the left hand side equation term to the right hand side then it will multiply in the numerator part of the right hand side equation term and vice versa for the case of denominator.
Complete step by step solution:
The given question is to simplify the fraction equation
\[\dfrac{{hi}}{{ho}} = - \dfrac{{di}}{{do}}\]
And to find the value of “do”
Assuming that the given terms in the fraction part are solely independent, that is the given variables can’t be reduced by cancelling the similar letters in denominator and numerator we get:
\[
\Rightarrow \dfrac{{hi}}{{ho}} = - \dfrac{{di}}{{do}} \\
\Rightarrow do \times \dfrac{{hi}}{{ho}} = - di \\
\Rightarrow do = - di \times \dfrac{{ho}}{{hi}} \\
\]
This is our final solution for the variable asked in the question.
Additional Information:Here you can also assume the terms as some other variable to get no confusion with the cross multiplication and getting the solution of the equation, but since there are only two –two variables written in the terms of fraction so you can solve directly also.
Note:To get solution of such question you need to clear with the cross multiplication rule, that is when you multiply the denominator of the left hand side equation term to the right hand side then it will multiply in the numerator part of the right hand side equation term and vice versa for the case of denominator.
Recently Updated Pages
Write structures of the following compounds i 2 Chloro3methylpentane class 11 chemistry CBSE

What is BLO What is the full form of BLO class 8 social science CBSE

Explain the Treaty of Vienna of 1815 class 10 social science CBSE

A Paragraph on Pollution in about 100-150 Words

XIX+XXX A 49 B 51 C 55 D 44 class 5 maths CBSE

If x a + bt + ct2 where x is in meters and t is in class 11 physics CBSE

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Find the value of the expression given below sin 30circ class 11 maths CBSE

What do you mean by retardation What is its SI uni class 11 physics CBSE

Draw a diagram of nephron and explain its structur class 11 biology CBSE

10 examples of friction in our daily life

Difference between physical and chemical change class 11 chemistry CBSE

