Solve $3x - 6 = 6$.
Answer
621k+ views
Hint: The above given expression is an example of a two step equation. In order to solve it we need to manipulate the given equation in such a way that we should get $x$ by itself. In order to get $x$ by itself we can perform any arithmetic operations on both LHS and RHS equally at the same time such that the equality of the given equation doesn’t change.
Complete step by step solution:
Given
$3x - 6 = 6..................................\left( i \right)$
Now in order to solve the given equation we need to solve for $x$.
Such that we have to manipulate the given equation in terms of only $x$, which can be achieved by performing different arithmetic operations on both LHS and RHS equally.
So to isolate the $x$ term from equation (i) we can add $6$ to both LHS and RHS, since adding $6$ to the
LHS will isolate the term $x$ alone by canceling the term $ - 6$.
Adding $6$ to both LHS and RHS of equation (i), we get:
\[3x - 6 + 6 = 6 + 6..........................\left( {ii} \right)\]
Now on solving (ii) we get:
\[
\Rightarrow 3x = 12 \\
\Rightarrow x = \dfrac{{12}}{3}.......................\left( {iii} \right) \\
\]
On simplifying (iii) we can write:
$
\Rightarrow x = \dfrac{{12}}{3} \\
\Rightarrow x = \dfrac{{4 \times 3}}{{1 \times 3}} \\
\Rightarrow x = 4....................\left( {iv} \right) \\
$
So on solving $3x - 6 = 6$, we get $x = 4$.
Therefore our final answer is $x = 4$.
Note:
A two-step equation is an algebraic equation which can be solved in two steps. The equation is said to be true when we find the value of the variable which makes the equation true. We can also check if the variable that we got is true or not by substituting the value of the variable back into the equation and checking whether it satisfies the given equation or not.
Complete step by step solution:
Given
$3x - 6 = 6..................................\left( i \right)$
Now in order to solve the given equation we need to solve for $x$.
Such that we have to manipulate the given equation in terms of only $x$, which can be achieved by performing different arithmetic operations on both LHS and RHS equally.
So to isolate the $x$ term from equation (i) we can add $6$ to both LHS and RHS, since adding $6$ to the
LHS will isolate the term $x$ alone by canceling the term $ - 6$.
Adding $6$ to both LHS and RHS of equation (i), we get:
\[3x - 6 + 6 = 6 + 6..........................\left( {ii} \right)\]
Now on solving (ii) we get:
\[
\Rightarrow 3x = 12 \\
\Rightarrow x = \dfrac{{12}}{3}.......................\left( {iii} \right) \\
\]
On simplifying (iii) we can write:
$
\Rightarrow x = \dfrac{{12}}{3} \\
\Rightarrow x = \dfrac{{4 \times 3}}{{1 \times 3}} \\
\Rightarrow x = 4....................\left( {iv} \right) \\
$
So on solving $3x - 6 = 6$, we get $x = 4$.
Therefore our final answer is $x = 4$.
Note:
A two-step equation is an algebraic equation which can be solved in two steps. The equation is said to be true when we find the value of the variable which makes the equation true. We can also check if the variable that we got is true or not by substituting the value of the variable back into the equation and checking whether it satisfies the given equation or not.
Recently Updated Pages
If x a + bt + ct2 where x is in meters and t is in class 11 physics CBSE

A car covers the first half distance between two places class 11 physics CBSE

The resultant of two vectors overrightarrow P and overrightarrow class 11 physics CBSE

Find the value of cos 135 class 11 maths CBSE

A mass M is held in place by an applied force F and class 11 physics CBSE

A solution of glucose in water is labelled as 10 dfracwv class 11 chemistry CBSE

Trending doubts
Find the value of the expression given below sin 30circ class 11 maths CBSE

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Draw a diagram of nephron and explain its structur class 11 biology CBSE

10 examples of friction in our daily life

Proton was discovered by A Thomson B Rutherford C Chadwick class 11 chemistry CBSE

Bond order ofO2 O2+ O2 and O22 is in order A O2 langle class 11 chemistry CBSE

