How do you solve $3\left( 2x-5 \right)=3\left( x+1 \right)$ ?

Hint: We can see that 3 is in LHS and RHS, so we can cancel out 3 both sides. Then the equation will be a linear equation in one variable, we can bring the variable to one side and constant to another side. Then divide both LHS and RHS by the coefficient of x to find the unknown.

Complete step by step answer:
The equation given in the question is $3\left( 2x-5 \right)=3\left( x+1 \right)$ which is a linear equation
We cancel out 3 both side
2x – 5=x + 1
Let bring the variable to LHS and constant to RHS we can see – 5 is there in LHS
We can add 5 to both LHS and RHS , so adding 2 both sides we get
$\Rightarrow 2x=x+6$
We can subtract x from both sides
$\Rightarrow x=6$
So the solution to $3x-2=8$ is equal to 6

Note:
We can solve this question by another method that is by graphical method we can draw the graph of y = 2x -5 and y = x + 1 , and we can check the intersection point that will be our solution. In this case both the equations are of straight line so there will be one intersection point at x = 6 and y = 7 . We know that the given equation is a linear equation which has only one unknown variable, but if a linear equation has n unknown variables, then we will need at least an equation to find the value of all variables.