How do you solve $2\left( 5x+1 \right)=3\left( 3x+7 \right)$?
Answer
609k+ views
Hint: We separate the variables and the constants of the equation $2\left( 5x+1 \right)=3\left( 3x+7 \right)$. We have in total two multiplications. We multiply the constants. Then we apply the binary operation of addition and subtraction for both variables and constants. The solutions of the variables and the constants will be added at the end to get the final answer to equate with 0. Then we solve the linear equation to find the value of x.
Complete step by step solution:
The given equation $2\left( 5x+1 \right)=3\left( 3x+7 \right)$ is a linear equation of x. We need to simplify the equation by completing the multiplication of the constants separately.
All the terms in the equation of $2\left( 5x+1 \right)=3\left( 3x+7 \right)$ are either variables of x or a constant. We break the multiplication by multiplying 2 with $\left( 5x+1 \right)$ and 3 with $\left( 3x+7 \right)$.
So, $2\left( 5x+1 \right)=10x+2$ and $3\left( 3x+7 \right)=9x+21$.
The equation becomes $10x+2=9x+21$.
We take all the variables and the constants on one side and get $10x+2-9x-21=0$.
There are two variables which are $10x,-9x$.
The binary operation between them is addition which gives us $10x-9x=x$.
Now we take the constants.
There are two such constants which are $2,-21$.
The binary operation between them is addition which gives us $2-21=-19$.
The final solution becomes
$\begin{align}
& 10x+2-9x-21=0 \\
& \Rightarrow x-19=0 \\
\end{align}$.
Now we take the variable on one side and the constants on the other side.
\[\begin{align}
& x-19=0 \\
& \Rightarrow x=19 \\
\end{align}\]
Therefore, the solution is $x=19$.
Note: To confirm the result of the solution being $x=19$ for equation $2\left( 5x+1 \right)=3\left( 3x+7 \right)$, we put the value on both sides of the equation and find the final value.
Therefore, the left-hand side of the equation becomes
\[2\left( 5x+1 \right)=2\left( 5\times 19+1 \right)=2\left( 95+1 \right)=2\times 96=192\]
The right-hand side of the equation becomes
\[3\left( 3x+7 \right)=3\left( 3\times 19+7 \right)=3\left( 57+7 \right)=3\times 64=192\]
Thus, verified for the equation $2\left( 5x+1 \right)=3\left( 3x+7 \right)$ the solution is $x=19$
Complete step by step solution:
The given equation $2\left( 5x+1 \right)=3\left( 3x+7 \right)$ is a linear equation of x. We need to simplify the equation by completing the multiplication of the constants separately.
All the terms in the equation of $2\left( 5x+1 \right)=3\left( 3x+7 \right)$ are either variables of x or a constant. We break the multiplication by multiplying 2 with $\left( 5x+1 \right)$ and 3 with $\left( 3x+7 \right)$.
So, $2\left( 5x+1 \right)=10x+2$ and $3\left( 3x+7 \right)=9x+21$.
The equation becomes $10x+2=9x+21$.
We take all the variables and the constants on one side and get $10x+2-9x-21=0$.
There are two variables which are $10x,-9x$.
The binary operation between them is addition which gives us $10x-9x=x$.
Now we take the constants.
There are two such constants which are $2,-21$.
The binary operation between them is addition which gives us $2-21=-19$.
The final solution becomes
$\begin{align}
& 10x+2-9x-21=0 \\
& \Rightarrow x-19=0 \\
\end{align}$.
Now we take the variable on one side and the constants on the other side.
\[\begin{align}
& x-19=0 \\
& \Rightarrow x=19 \\
\end{align}\]
Therefore, the solution is $x=19$.
Note: To confirm the result of the solution being $x=19$ for equation $2\left( 5x+1 \right)=3\left( 3x+7 \right)$, we put the value on both sides of the equation and find the final value.
Therefore, the left-hand side of the equation becomes
\[2\left( 5x+1 \right)=2\left( 5\times 19+1 \right)=2\left( 95+1 \right)=2\times 96=192\]
The right-hand side of the equation becomes
\[3\left( 3x+7 \right)=3\left( 3\times 19+7 \right)=3\left( 57+7 \right)=3\times 64=192\]
Thus, verified for the equation $2\left( 5x+1 \right)=3\left( 3x+7 \right)$ the solution is $x=19$
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