What is the solution to the proportion \[\dfrac{x}{2} = \dfrac{5}{{15}}\]?
Answer
590.7k+ views
Hint: Two numbers are said to be proportional to each other, if one number has a constant ratio to another number.
The proportional relationships are relationships between two variables where their ratios are equivalent. Another way to think about them is that, in a proportional relationship, one variable is always a constant value times the other. That constant is known as the "constant of proportionality".
i.e. if the ratio \[\dfrac{y}{x}\] of two variables \[\left( {x{\text{ }}\& y} \right)\] is equal to a constant $k$, then the variable in the numerator of the ratio \[(y)\] is the product of the other variable and the constant
\[y = k \times x\] .
In this case $y$ is said to be directly proportional to $x$ with proportionality constant $k$.
If \[a,{\text{ }}b,{\text{ }}c,{\text{ }}d\] are proportional , then they will have the same proportionality constant.
(i.e.) \[\dfrac{a}{b} = \dfrac{c}{d}\]
We will apply the same in our given proportion and we will get an equation.
Then by cross multiplication of the terms, we will get the value of $x$ .
Complete step-by-step solution:
It is given that, \[\dfrac{x}{2} = \dfrac{5}{{15}}\] are in proportion.
We need to find out the value of $x$.
Now , we solve it by a special method,
Multiply the known corners and divide by the third number.
\[x = \dfrac{{2 \times 5}}{{15}}\]
On solving the above equation, we have,
\[x = \dfrac{{10}}{{15}}\]
Hence, \[x = \dfrac{{10}}{{15}}\].
Now , we will divide the numerator and denominator by the common term, we get,
Hence the value of $x$ is \[\dfrac{2}{3}\] which is the required answer for the given question.
Note: If \[x,{\text{ }}y,{\text{ }}z\] are in proportion then, \[\dfrac{x}{y} = \dfrac{y}{z}\] .
If\[a,{\text{ }}b,{\text{ }}c,{\text{ }}d\] are proportional, then they will have the same proportionality constant.
(i.e.)\[\dfrac{a}{b} = \dfrac{c}{d}\].
Here we can also elaborate the problem as equivalent fractions that means their simplified forms are equal.
The proportional relationships are relationships between two variables where their ratios are equivalent. Another way to think about them is that, in a proportional relationship, one variable is always a constant value times the other. That constant is known as the "constant of proportionality".
i.e. if the ratio \[\dfrac{y}{x}\] of two variables \[\left( {x{\text{ }}\& y} \right)\] is equal to a constant $k$, then the variable in the numerator of the ratio \[(y)\] is the product of the other variable and the constant
\[y = k \times x\] .
In this case $y$ is said to be directly proportional to $x$ with proportionality constant $k$.
If \[a,{\text{ }}b,{\text{ }}c,{\text{ }}d\] are proportional , then they will have the same proportionality constant.
(i.e.) \[\dfrac{a}{b} = \dfrac{c}{d}\]
We will apply the same in our given proportion and we will get an equation.
Then by cross multiplication of the terms, we will get the value of $x$ .
Complete step-by-step solution:
It is given that, \[\dfrac{x}{2} = \dfrac{5}{{15}}\] are in proportion.
We need to find out the value of $x$.
Now , we solve it by a special method,
Multiply the known corners and divide by the third number.
\[x = \dfrac{{2 \times 5}}{{15}}\]
On solving the above equation, we have,
\[x = \dfrac{{10}}{{15}}\]
Hence, \[x = \dfrac{{10}}{{15}}\].
Now , we will divide the numerator and denominator by the common term, we get,
Hence the value of $x$ is \[\dfrac{2}{3}\] which is the required answer for the given question.
Note: If \[x,{\text{ }}y,{\text{ }}z\] are in proportion then, \[\dfrac{x}{y} = \dfrac{y}{z}\] .
If\[a,{\text{ }}b,{\text{ }}c,{\text{ }}d\] are proportional, then they will have the same proportionality constant.
(i.e.)\[\dfrac{a}{b} = \dfrac{c}{d}\].
Here we can also elaborate the problem as equivalent fractions that means their simplified forms are equal.
Recently Updated Pages
You are the head boyhead girl Write a notice informing class 7 english CBSE

The image formed by a plane mirror is always laterally class 7 physics CBSE

When phenolphthalein is added toNaOH the colour of class 7 chemistry CBSE

Find the least number which when divided by 15 leaves class 7 maths CBSE

Show that one and only one out of n n + 2n or n + -class-7-maths-CBSE

During heavy exercise we get cramps in the legs due class 7 biology CBSE

Trending doubts
Full Form of IASDMIPSIFSIRSPOLICE class 7 social science CBSE

List of coprime numbers from 1 to 100 class 7 maths CBSE

The plural of Chief is Chieves A True B False class 7 english CBSE

The founder of Jainism was A Rishabhadev B Neminath class 7 social science CBSE

Collective noun a of sailors class 7 english CBSE

Differentiate between weather and climate How do they class 7 social science CBSE


