Simplify $\dfrac{3-2i}{-4-i}$ ?
Answer
615.3k+ views
Hint: Here we know that the given above equation is the form of division it basically form of complex numbers, where in the above equation we have to multiply both the numerator as well as the denominator with its conjugates to solve it further.
Complete step by step solution:
In the given numerical we know I is the form of complex number but the form of division, where we have to multiply the equation with its conjugates,
So we have to use the formula of division are as follow,
\[\dfrac{a+bi}{c+di}=\dfrac{\left( a+bi \right)\left( c-di \right)}{\left( c+di \right)\left( c-di \right)}\]
As we know that we have to multiply the equation with its conjugates,
Thus substituting the equation in the division formula we get,
\[\dfrac{3-2i}{-4-i}=\dfrac{\left( 3-2i \right)\left( -4+i \right)}{\left( -4-i \right)\left( -4+i \right)}\]
So in the above equation we have multiply with its \[\left( -4+i \right)\] both with numerator as well as denominator,
Further opening the bracket we get, multiplying \[\left( 3-2i \right)\left( -4+i \right)\]
So we have to multiply with three into four, again three with i,\[-2i\] with \[-4\] and \[-2i\] with I we get,
\[=\dfrac{-12+3i+8i-2{{i}^{2}}}{\left( -4-i \right)\left( -4+i \right)}\]
Again opening the lower bracket we have to multiply \[\left( -4-i \right)\left( -4+i \right)\], here we are multiplying \[-4\] with \[-4\] , \[-4\] with \[i,-i\] with \[-4\] and \[i\] with \[+i\] thus we obtained.
\[\dfrac{-12+3i+8i-2{{i}^{2}}}{16-4i+4i-{{i}^{2}}}\]
Here we will add the value of \[3i+8i\] were we are going to obtained as \[11i\] also when we are adding \[4i\] with \[+4i\] it will going to cancel it each other and remaining will be zero.
\[=\dfrac{-12+11i-2{{i}^{2}}}{16-{{i}^{2}}}\]
We know that the value of \[{{i}^{2}}=-1\] so substituting the value in above equation we get,
\[=\dfrac{-12+11i-2\left( -1 \right)}{16-\left( -1 \right)}\]
So further solving the above equation we get as
\[=\dfrac{-10+11i}{17}\]
Hence while solving the above numerical we get the value as \[=\dfrac{-10+11i}{17}\]
Note: First we had to identify the equation of complex number then we have to look its division farm, Applying the division rule, solve equation using BODMAS rule,
Remember the value of \[{{i}^{2}}=1\]
Complete step by step solution:
In the given numerical we know I is the form of complex number but the form of division, where we have to multiply the equation with its conjugates,
So we have to use the formula of division are as follow,
\[\dfrac{a+bi}{c+di}=\dfrac{\left( a+bi \right)\left( c-di \right)}{\left( c+di \right)\left( c-di \right)}\]
As we know that we have to multiply the equation with its conjugates,
Thus substituting the equation in the division formula we get,
\[\dfrac{3-2i}{-4-i}=\dfrac{\left( 3-2i \right)\left( -4+i \right)}{\left( -4-i \right)\left( -4+i \right)}\]
So in the above equation we have multiply with its \[\left( -4+i \right)\] both with numerator as well as denominator,
Further opening the bracket we get, multiplying \[\left( 3-2i \right)\left( -4+i \right)\]
So we have to multiply with three into four, again three with i,\[-2i\] with \[-4\] and \[-2i\] with I we get,
\[=\dfrac{-12+3i+8i-2{{i}^{2}}}{\left( -4-i \right)\left( -4+i \right)}\]
Again opening the lower bracket we have to multiply \[\left( -4-i \right)\left( -4+i \right)\], here we are multiplying \[-4\] with \[-4\] , \[-4\] with \[i,-i\] with \[-4\] and \[i\] with \[+i\] thus we obtained.
\[\dfrac{-12+3i+8i-2{{i}^{2}}}{16-4i+4i-{{i}^{2}}}\]
Here we will add the value of \[3i+8i\] were we are going to obtained as \[11i\] also when we are adding \[4i\] with \[+4i\] it will going to cancel it each other and remaining will be zero.
\[=\dfrac{-12+11i-2{{i}^{2}}}{16-{{i}^{2}}}\]
We know that the value of \[{{i}^{2}}=-1\] so substituting the value in above equation we get,
\[=\dfrac{-12+11i-2\left( -1 \right)}{16-\left( -1 \right)}\]
So further solving the above equation we get as
\[=\dfrac{-10+11i}{17}\]
Hence while solving the above numerical we get the value as \[=\dfrac{-10+11i}{17}\]
Note: First we had to identify the equation of complex number then we have to look its division farm, Applying the division rule, solve equation using BODMAS rule,
Remember the value of \[{{i}^{2}}=1\]
Recently Updated Pages
If x a + bt + ct2 where x is in meters and t is in class 11 physics CBSE

A car covers the first half distance between two places class 11 physics CBSE

The resultant of two vectors overrightarrow P and overrightarrow class 11 physics CBSE

Find the value of cos 135 class 11 maths CBSE

A mass M is held in place by an applied force F and class 11 physics CBSE

A solution of glucose in water is labelled as 10 dfracwv class 11 chemistry CBSE

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Find the value of the expression given below sin 30circ class 11 maths CBSE

Draw a diagram of nephron and explain its structur class 11 biology CBSE

10 examples of friction in our daily life

Proton was discovered by A Thomson B Rutherford C Chadwick class 11 chemistry CBSE

Bond order ofO2 O2+ O2 and O22 is in order A O2 langle class 11 chemistry CBSE

