Rest mass of photon is
$\begin{gathered}
  A.\dfrac{{hv}}{{{c^2}}} \\
  B.\dfrac{{hv}}{c} \\
  C.hv \\
  D.zero \\
\end{gathered} $

Hint: In such a type of question we need to explain about the basic properties of the photon, as explaining its property we can finally find the required answer. Need to explain its property too.

Complete Step-by-Step solution:
Photon is a subatomic molecule,
p
or on the other hand
p+
with a positive electric charge of +1e rudimentary charge and a mass marginally not as much as that of a neutron. Protons and neutrons, each with masses of around one nuclear mass unit, are on the whole alluded to as "nucleons" (particles present in nuclear cores).
At least one photon is available in the core of each iota; they are an important piece of the core. The quantity of protons in the core is the characterizing property of a component, and is alluded to as the nuclear number (spoken to by the image Z). Since every component has an exceptional number of protons, every component has its own one of a kind nuclear number.
The rest mass of photons is zero which is given according to the general relativity theory of light.
Therefore option D is Correct.

Note: In this question we had to explain about the rest mass of the photon, as we gave some of the basic knowledge about the photons and also about its subatomic particles. We gave all the required details to gain our required answer.