How many resonance structures can be drawn for ${{N}_{2}}O$ ?

Hint:Lewis dot structures also known as Lewis electron-dot formulas. It uses dots arranged around the chemical symbol for an element to represent the valence electron configuration of the atoms in the element.

Complete answer:
When we draw two or more than two Lewis dot structures for a molecule, which differs only in the locations of the electrons then we draw the resonance structure for those molecules. The actual structure is the resonance hybrid of all of the structures.
To draw the structure first we will calculate the number of valence electrons present in the given compound:
The number of valence electrons in nitrogen = 5
And the number of valence electrons in oxygen = 6
Total number of valence electrons in the compound
\[\begin{align}
  & =(5\times 2)+(6\times 1) \\
 & =16 \\
\end{align}\]
There are a total of 16 valence electrons present in ${{N}_{2}}O$. After this we should follow the octet rule in filling electrons in the outer orbital. So, we will form covalent bonds between two atoms which are formed by sharing electrons from one electron from each atom. The resonance structures are made by the delocalisation of electrons.

Hence, there are 3 resonance structures for ${{N}_{2}}O$.

Note:
In general, when we have to solve the question from organic chemistry be careful with the inductive and resonance effect as in many of the cases resonance effect is stronger and in many cases inductive effect is stronger as compared to resonance effect.