What is the relation between thrust and pressure?
${\text{A}}{\text{.}}$ Pressure directly proportional to thrust
${\text{B}}{\text{.}}$ Pressure indirectly proportional to thrust
${\text{C}}{\text{.}}$ No relation
${\text{D}}{\text{.}}$ None

Hint: Here, we will proceed by defining the term pressure widely used in physics. Then, we will write down its mathematical formula along with its S.I units. Finally, we will mention the difference between thrust and force.

Complete step-by-step answer:

Pressure is defined as the measure of force per unit area. It can also be defined as the ratio of the force applied to the area on which it is applied.

Pressure = $\dfrac{{{\text{Force}}}}{{{\text{Area}}}}$

The S.I unit of force is newton (N) and the S.I unit of area is square metre (${{\text{m}}^2}$). So, the S.I unit of pressure will be newton per square metre (N/${{\text{m}}^2}$) which is also called Pascal (Pa).

1 Pa = 1 N/${{\text{m}}^2}$

Force simply refers to push or pull on an object whereas thrust refers to the reaction force acting on an accelerated object due to the force which is applied to that object.
Thrust is also defined as the magnitude of the force. Both force and thrust have same S.I unit which is newton (N)

The relation between pressure and thrust is given by

Pressure = $\dfrac{{{\text{Thrust}}}}{{{\text{Area}}}}$

From the above equation, we can clearly see that the pressure is directly proportional to the pressure.

i.e., Pressure $ \propto $ Thrust

Therefore, the relationship between thrust and pressure is that pressure is directly proportional to thrust.

Hence, option A is correct.

Note: In this particular problem, if we are asked for the relationship between pressure and area on which this pressure is applied. We can clearly see from the formula i.e., Pressure = $\dfrac{{{\text{Force}}}}{{{\text{Area}}}}$, that the pressure is inversely proportional to the area. Here, if the thrust will increase then the pressure will also increase.