In an examination it is required to get 540 of the aggregate marks to pass. A student gets 432 marks and is failed by 9% marks. How much maximum aggregate marks a student can get?
A. 1475
B. 1350
C. 1200
D. 1000

Hint: Student is failed by 9% means that marks by which student failed is the 9% of the maximum aggregate marks.

Complete step-by-step answer:
Let the maximum aggregate marks a student can get be x.

And as we know, the aggregate marks required to pass is 540.

And students get 432 marks.

So, a student is failed by (aggregate marks required to pass – marks of student ) marks = 540 – 432 = 108 marks.

Now we are given the question that a student has failed by 9%.

So, 108 will be the 9% of maximum aggregate marks a student can get (i.e. x).

As we know by the formula to find the percentage that if total marks are y then z% of y is calculated as \[\left( {\dfrac{{\text{z}}}{{{\text{100}}}}} \right) \times \left( {\text{y}} \right)\].

So, 9% of x will be calculated as \[\left( {\dfrac{9}{{{\text{100}}}}} \right)\times \left( {\text{x}} \right)\].

So, as proved above \[\left( {\dfrac{9}{{{\text{100}}}}} \right) \times \left( {\text{x}} \right)\] = 108.

Now we had to solve the above equation to find the value of x.

So, multiplying both sides of the above equation by \[\dfrac{{100}}{9}\]. We get,

x = \[\left( {\dfrac{{{\text{100}}}}{{\text{9}}}} \right) \times \left( {{\text{108}}} \right)\] = 100 \[\times\] 12 = 1200.

So, the maximum aggregate marks a student can get is equal to 1200.

Hence, the correct option will be C.

Note: Whenever we come up with this type of problem then first, we will assume total aggregate marks as x. And then we will find marks by which students fail. After that by manipulating the percentage formula we easily get the required value of x. And this will be the easiest and efficient way to find the solution of the problem.