If I dropped a circular, triangular, and square parachute from the same height which will land first assuming the parachuted object's weight is the same and the surface area is the same for all three parachutes?

Hint: We will answer the above question with respect to drag force. It is observed that the intensity of the drag force is related to the square of the object's speed. presuming that the parachutes are flat, horizontal plates with negligible or equal drag forces owing to the load and lines connecting the load to the parachute.

Complete answer:
The parachute descending through the air while being influenced by gravity. The gravitational force and the drag force are the two forces acting on it. Gravity's downward force is constant regardless of the speed at which the parachute is going. However, when a parachute’s velocity rises, the magnitude of the drag force rises as well, until the drag force equals the gravitational force, resulting in a net force of zero. Newton's second law states that there is no acceleration if the net force is zero. The person's velocity remains constant at this point, and we say the parachute has reached its terminal velocity.
 Experimentally established drag coefficients for the three forms a circular, triangular, and square.
 $ {F_D} = \dfrac{1}{2}C\rho A{v^2} $
gives the drag force. where $ A $ is the area, $ v $ is the speed of descent in still air, and $ \rho $ is the density of the air and $ C $ is the drag coefficient.
As a result, the circular parachute experiences the least drag and hence reaches the ground first.

Note:
The drag force resists an object's motion at all times. A parachute is a device that creates drag to slow the speed of an item through the atmosphere. For low-speed flow, drag force is related to velocity, and for high-speed flow, drag force is proportional to square velocity, where the difference between low and high speed is measured by the Reynolds number.