If ${{a}_{1}},{{a}_{2}},..{{a}_{n}}$ are positive real numbers whose product is a fixed number c, then the minimum value of ${{a}_{1}}+{{a}_{2}}+...{{a}_{n-1}}+2{{a}_{n}}$.
A. $n{{\left( 2c \right)}^{1/n}}$
B. $(n+1){{c}^{1/n}}$
C. $2n{{c}^{1/n}}$
D. $(n+1){{(2c)}^{1/n}}$
Answer
620.4k+ views
Hint: The given problem statement is very simple: you just need to apply basic logic with that you also need to apply the concept of the arithmetic mean and geometric mean. Now, you can simply solve the problem statement. So, let’s see what will be the approach for the given problem statement.
Step-By-Step Solution:
The given problem statement is to find the minimum value of${{a}_{1}}+{{a}_{2}}+...{{a}_{n-1}}+2{{a}_{n}}$, when ${{a}_{1}},{{a}_{2}},..{{a}_{n}}$are positive real numbers whose product is a fixed number c.
So, we have ${{a}_{1}},{{a}_{2}},{{a}_{3}},....,{{a}_{n}}=c$
Now, we will multiply both sides by 2 in the above equation, that means, we get,
$\Rightarrow {{a}_{1}},{{a}_{2}},{{a}_{3}},....,2{{a}_{n}}=2c$… (i)
As we know that for n positive numbers the arithmetic mean is greater than or equal to geometric mean, that means, we get,
Arithmetic Mean $\ge $ Geometric Mean
$\Rightarrow \dfrac{{{a}_{1}}+{{a}_{2}}+{{a}_{3}}+.....+{{a}_{n-1}}+2{{a}_{n}}}{n}\ge \sqrt[n]{{{a}_{1}},{{a}_{2}},{{a}_{3}},....(2{{a}_{n}})}$
From the equation (i), we can get,
$\Rightarrow \dfrac{{{a}_{1}}+{{a}_{2}}+{{a}_{3}}+.....+{{a}_{n-1}}+2{{a}_{n}}}{n}\ge \sqrt[n]{2c}$
Now, we will take the n from left-hand side to right-hand side and it will be in the form of multiplication on the right-hand side. Also, we will rearrange n square root to$\dfrac{1}{n}$, that means, we get,
$\Rightarrow {{a}_{1}}+{{a}_{2}}+{{a}_{3}}+.....+{{a}_{n-1}}+2{{a}_{n}}\ge n.{{(2c)}^{\dfrac{1}{n}}}$
Therefore, we get the minimum value of${{a}_{1}}+{{a}_{2}}+{{a}_{3}}+......{{a}_{n-1}}+2{{a}_{n}}$ is $n.{{(2c)}^{\dfrac{1}{n}}}$.
So, the correct answer is option A.
Note:
So, from the given problem statement we learnt the concept of the arithmetic mean and geometric mean. We just need to note that whenever there are n positive numbers at that point of time the arithmetic mean is greater than or equal to the geometric mean.
Step-By-Step Solution:
The given problem statement is to find the minimum value of${{a}_{1}}+{{a}_{2}}+...{{a}_{n-1}}+2{{a}_{n}}$, when ${{a}_{1}},{{a}_{2}},..{{a}_{n}}$are positive real numbers whose product is a fixed number c.
So, we have ${{a}_{1}},{{a}_{2}},{{a}_{3}},....,{{a}_{n}}=c$
Now, we will multiply both sides by 2 in the above equation, that means, we get,
$\Rightarrow {{a}_{1}},{{a}_{2}},{{a}_{3}},....,2{{a}_{n}}=2c$… (i)
As we know that for n positive numbers the arithmetic mean is greater than or equal to geometric mean, that means, we get,
Arithmetic Mean $\ge $ Geometric Mean
$\Rightarrow \dfrac{{{a}_{1}}+{{a}_{2}}+{{a}_{3}}+.....+{{a}_{n-1}}+2{{a}_{n}}}{n}\ge \sqrt[n]{{{a}_{1}},{{a}_{2}},{{a}_{3}},....(2{{a}_{n}})}$
From the equation (i), we can get,
$\Rightarrow \dfrac{{{a}_{1}}+{{a}_{2}}+{{a}_{3}}+.....+{{a}_{n-1}}+2{{a}_{n}}}{n}\ge \sqrt[n]{2c}$
Now, we will take the n from left-hand side to right-hand side and it will be in the form of multiplication on the right-hand side. Also, we will rearrange n square root to$\dfrac{1}{n}$, that means, we get,
$\Rightarrow {{a}_{1}}+{{a}_{2}}+{{a}_{3}}+.....+{{a}_{n-1}}+2{{a}_{n}}\ge n.{{(2c)}^{\dfrac{1}{n}}}$
Therefore, we get the minimum value of${{a}_{1}}+{{a}_{2}}+{{a}_{3}}+......{{a}_{n-1}}+2{{a}_{n}}$ is $n.{{(2c)}^{\dfrac{1}{n}}}$.
So, the correct answer is option A.
Note:
So, from the given problem statement we learnt the concept of the arithmetic mean and geometric mean. We just need to note that whenever there are n positive numbers at that point of time the arithmetic mean is greater than or equal to the geometric mean.
Recently Updated Pages
If x a + bt + ct2 where x is in meters and t is in class 11 physics CBSE

A car covers the first half distance between two places class 11 physics CBSE

The resultant of two vectors overrightarrow P and overrightarrow class 11 physics CBSE

Find the value of cos 135 class 11 maths CBSE

A mass M is held in place by an applied force F and class 11 physics CBSE

A solution of glucose in water is labelled as 10 dfracwv class 11 chemistry CBSE

Trending doubts
Find the value of the expression given below sin 30circ class 11 maths CBSE

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Draw a diagram of nephron and explain its structur class 11 biology CBSE

10 examples of friction in our daily life

Proton was discovered by A Thomson B Rutherford C Chadwick class 11 chemistry CBSE

Bond order ofO2 O2+ O2 and O22 is in order A O2 langle class 11 chemistry CBSE

