How do you solve ${x^2} - 20 = 0?$ ?
Answer
628.5k+ views
Hint: Use quadratic equation formula to solve the equation.
Quadratic equation: Quadratic equations are the polynomial equations of degree two in one variable. The degree of the polynomial is the highest power of the variable in the equation. The general form of quadratic equation is $f\left( x \right) = a{x^2} + bx + c$ where $a,b$ and $c$, belongs to real numbers and the coefficients of the ${x^2}$ is known as leading coefficient and $c$ is called constant absolute term of $f\left( x \right)$.
The values of $x$ satisfying the quadratic equation are the roots of the quadratic equation.
A quadratic equation will always have two roots. The nature of roots can be either real or imaginary.
A quadratic polynomial, when equated to zero becomes a quadratic equation.
A quadratic equation becomes an identity $\left( {a,b,c = 0} \right)$ if the equation is satisfied by more than two numbers, having more than two roots or solutions either real or complex.
Formula Used: Formula for finding the roots of quadratic equation is,
$\left( {m,n} \right) = \dfrac{{ - b \pm \sqrt {{b^2} - 4ac} }}{{2a}}$
Where m and n are the roots of the quadratic equation,
$f\left( x \right) = a{x^2} + bx + c$.
Complete step-by-step answer:
Step: 1 Compare the equation ${x^2} - 20 = 0$ with the quadratic equation $f\left( x \right) = a{x^2} + bx + c$.
$
\Rightarrow a = 1 \\
\Rightarrow b = 0 \\
\Rightarrow c = - 20 \\
$
Substitute the values in the formula to find the root of the equation.
Suppose $\left( {m,n} \right)$are roots of the equation.
$
\left( {m,n} \right) = \dfrac{{ - b \pm \sqrt {{b^2} - 4ac} }}{{2a}} \\
\Rightarrow \left( {m,n} \right) = \dfrac{{ - 0 \pm \sqrt {0 - 4 \times 1 \times \left( { - 20} \right)} }}{{2 \times 1}} \\
\Rightarrow \left( {m,n} \right) = \pm \sqrt {20} \\
$
Therefore the roots of the quadratic equations are $ \pm \sqrt {20} $.
Note:
Students must remember the formula to find roots of the quadratic equation.
They must compare the given quadratic equation with the general form of quadratic equation and find the values of the respective coefficients. Students are advised to not make any mistake in writing the formula of quadratic equations. Students should use an alternative method to find the solutions.
Alternative method:
The equation is ${x^2} - 20 = 0$.
Quadratic equation: Quadratic equations are the polynomial equations of degree two in one variable. The degree of the polynomial is the highest power of the variable in the equation. The general form of quadratic equation is $f\left( x \right) = a{x^2} + bx + c$ where $a,b$ and $c$, belongs to real numbers and the coefficients of the ${x^2}$ is known as leading coefficient and $c$ is called constant absolute term of $f\left( x \right)$.
The values of $x$ satisfying the quadratic equation are the roots of the quadratic equation.
A quadratic equation will always have two roots. The nature of roots can be either real or imaginary.
A quadratic polynomial, when equated to zero becomes a quadratic equation.
A quadratic equation becomes an identity $\left( {a,b,c = 0} \right)$ if the equation is satisfied by more than two numbers, having more than two roots or solutions either real or complex.
Formula Used: Formula for finding the roots of quadratic equation is,
$\left( {m,n} \right) = \dfrac{{ - b \pm \sqrt {{b^2} - 4ac} }}{{2a}}$
Where m and n are the roots of the quadratic equation,
$f\left( x \right) = a{x^2} + bx + c$.
Complete step-by-step answer:
Step: 1 Compare the equation ${x^2} - 20 = 0$ with the quadratic equation $f\left( x \right) = a{x^2} + bx + c$.
$
\Rightarrow a = 1 \\
\Rightarrow b = 0 \\
\Rightarrow c = - 20 \\
$
Substitute the values in the formula to find the root of the equation.
Suppose $\left( {m,n} \right)$are roots of the equation.
$
\left( {m,n} \right) = \dfrac{{ - b \pm \sqrt {{b^2} - 4ac} }}{{2a}} \\
\Rightarrow \left( {m,n} \right) = \dfrac{{ - 0 \pm \sqrt {0 - 4 \times 1 \times \left( { - 20} \right)} }}{{2 \times 1}} \\
\Rightarrow \left( {m,n} \right) = \pm \sqrt {20} \\
$
Therefore the roots of the quadratic equations are $ \pm \sqrt {20} $.
Note:
Students must remember the formula to find roots of the quadratic equation.
They must compare the given quadratic equation with the general form of quadratic equation and find the values of the respective coefficients. Students are advised to not make any mistake in writing the formula of quadratic equations. Students should use an alternative method to find the solutions.
Alternative method:
The equation is ${x^2} - 20 = 0$.
Recently Updated Pages
A Paragraph on Pollution in about 100-150 Words

What is BLO What is the full form of BLO class 8 social science CBSE

10 examples of friction in our daily life

Draw a diagram of nephron and explain its structur class 11 biology CBSE

Write structures of the following compounds i 2 Chloro3methylpentane class 11 chemistry CBSE

XIX+XXX A 49 B 51 C 55 D 44 class 5 maths CBSE

Trending doubts
Explain the Treaty of Vienna of 1815 class 10 social science CBSE

Which is the Lowest Point of Earth?

1 GB equals how many MB?

10 examples of evaporation in daily life with explanations

What is the full form of POSCO class 10 social science CBSE

Make a sketch of the human nerve cell What function class 10 biology CBSE

