How do you solve for p in \[r{\text{ }} = {\text{ }}wp\] ?

Hint: To solve this question for p in the given expression , \[r{\text{ }} = {\text{ }}wp\] . There are 3 terms in our expression , for which we can perform the calculations . We can apply the concept of “ equivalent ” which refers to the equal to in quantity . And when we merge the word “ equation “ with this then the complete term is made up of “ equivalent equation ” . This actually means that the equivalent equations are the equations that may have the same solutions . To find the solution of algebra equivalent equations makes it easier .

Complete step-by-step answer:
Given,
 \[r{\text{ }} = {\text{ }}wp\]
We will solve for p in our question given , \[r{\text{ }} = {\text{ }}wp\]
To solve for the p , we will divide the expression by ‘ w ‘ both the sides .
We get ,
 \[\dfrac{r}{w}{\text{ }} = {\text{ }}p\]
Rearranging the equation ,
 \[\Rightarrow p = \dfrac{r}{w}{\text{ }}\]
This is our required solution .
So, the correct answer is \[p = \dfrac{r}{w}{\text{ }}\] ”.

Note: In equivalent equations which have identical solution we can perform addition or subtraction by the same number to both L.H.S. and R.H.S. of an equation .
> In equivalent equations which have identical solutions we can perform multiplication or division by the same non-zero number both L.H.S. and R.H.S. of an equation .
> In an equivalent equation which has an identical solution we can take the same odd square root to both L.H.S. and R.H.S. of an equation .
> In equivalent equations which have identical solutions we can raise the same odd power to both L.H.S. and R.H.S. of an equation .