How do you solve for h in $S = 2B + Ph$

Hint: This problem comes under different kinds of thinking that the three are different terms contained in the equation. We need to solve for h in the equation for that we separate h from the equation with basic mathematical operation. This kind of problem is not algebraic but solving on different terms with the required solvable term.

Complete step-by-step solution:
First consider the solvable term
Now, we are asked to solve for h in this equation, for that we need to separate h in the equation
Step 1: Now, subtract $2B$ on both sides of equation (1), we get
$ \Rightarrow S - 2B = 2B + Ph - 2B$
Step 2: Now cancelling $2B$ on right hand side of the above equation because the same number with different signs gets cancelled becomes zero, then we get
$ \Rightarrow S - 2B = Ph$
Step 3: Now divide $P$ on both sides of the above equation, we get
$ \Rightarrow \dfrac{{S - 2B}}{P} = \dfrac{{Ph}}{P}$
Step 4: Now cancelling $P$ on right hand side of the above equation because the same number we divide gets value 1, then we get
$ \Rightarrow \dfrac{{S - 2B}}{P} = h$

Thus, we solve for the value of h, $h = \dfrac{{S - 2B}}{P}$

Note: The problem related to this will be different when it has to find the solution for a separate variable by the methods of elimination. In that the particular term has need to solve means has to find the value of it. If the remaining variable values are given then the solution will be in numerical for the given term. Like this we need to solve value for the term we need to keep simple as we are familiar in it.