How do you solve $\dfrac{u}{5}+6=2$?

Hint: Perform arithmetic operations as per requirement of the question. Keeping ‘u’ on one side of the equation first try to wipe all addition or subtraction terms by adding or subtracting the required value present on the ‘u’ side of the equation. Then on the same side perform multiplication or division operation by multiplying or dividing the required value, for which only ‘u’ will be left on that particular side which will be independent of any coefficient or any adding or subtracting term and on the other side it’s value can be obtained.

Complete step by step answer:
To solve the equation $\dfrac{u}{5}+6=2$ means we have to find the value of ‘u’ for which the equation gets satisfied.
Considering equation $\dfrac{u}{5}+6=2$,
Subtracting ‘6’ from both the sides, we get
$\begin{align}
  & \Rightarrow \dfrac{u}{5}+6-6=2-6 \\
 & \Rightarrow \dfrac{u}{5}=-4 \\
\end{align}$
Now multiplying by ‘5’ on both the sides, we get
$\Rightarrow \dfrac{u}{5}\times 5=-4\times 5$
Since ‘5’ got cancelled both from numerator and denominator, hence we get
$\Rightarrow u=-20$
This is the solution of the above equation.

Note:
Operations like addition or subtraction should be done first and multiplication or division later for such a particular question. Because first we have to simplify by adding or subtracting so that it can be further simplified by, multiplying or dividing on the very next step. For example in the above question if we first multiply by ‘5’ and then then subtracting ‘6’ from both the sides
$\begin{align}
  & \dfrac{u}{5}+6=2 \\
 & \Rightarrow \left( \dfrac{u}{5}+6 \right)\times 5=2\times 5 \\
 & \Rightarrow \dfrac{u}{5}\times 5+6\times 5=10 \\
 & \Rightarrow u+30=10 \\
 & \Rightarrow u+30-6=10-6 \\
 & \Rightarrow u+24=4 \\
 & \Rightarrow u=4-24 \\
 & \Rightarrow u=-20 \\
\end{align}$
We are getting the same value but there are more complex calculations which will lead to more mistakes.