How do you solve \[8x-3x-10=20\]?

Hint: To solve this question we just need the basic knowledge of solving a linear equation. First we will rearrange all the like terms into one side. After that we will apply simple simplification techniques like adding a term on both sides, dividing with a term on both sides etc., to arrive at our solution.

Complete step by step answer:
Given equation is \[8x-3x-10=20\]
In the first step we have to rearrange all the like terms in the equation.
In our equation we have two terms containing x so we can take variable x as common on the LHS side. Then the equation will become Like this
\[\Rightarrow x\left( 8-3 \right)-10=20\]
Now we have to calculate the value that was obtained while taking x as common. After calculating the value the equation will look like this
\[\Rightarrow 5x-10=20\]
Now we have arrived at the equation from which we can know the value of x by simplification.
So we have to apply some simplification techniques to find the value of x.
Now we are going to add 10 on both sides of the equation. Then the equation will look like
\[\Rightarrow 5x-10+10=20+10\]
By calculating the above equation we get
\[\Rightarrow 5x=30\]
Now we have to divide the equation with 5 on both sides of equation then we will get
\[\Rightarrow \dfrac{5x}{5}=\dfrac{30}{5}\]
From this we get
\[x=6\]
So from the equation we will get \[x=6\].

Note:
We can also solve the equation by transferring the 10 to RHS side and then performing the necessary operations needed to arrive at the solution. Likewise we have many more ways to solve the given equation.